如何從DATABSE獲得價值並將其設置在PHP

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image for the result我試圖從DATABSE獲得價值並將其設置爲下拉框下拉列表但它沒有得到任何價值這裏是我的代碼如何從DATABSE獲得價值並將其設置在PHP

<?php 
$sql=mysqli_query("SELECT RoomTypeId from roomtypemaster"); 
if(mysqli_num_rows($sql)){ 
echo '<select name="select">'; 
while($rs=mysqli_fetch_array($sql)){ 
     echo '<option value="'.$rs['RoomTypeId'].'">'.$rs['RoomTypeId'].'</option>'; 

    } 
} 
echo '</select>'; 
    ?>

來源

2017-06-14 Yogesh

檢查的print_r（mysqli_fetch_array（$ SQL））有數據或者沒有 –

首先哪裏是你的數據庫連接變量 – JYoThI

mysqli_query至少需要兩個參數 –

mysqli_query函數佔用至少兩個參數。您在調用mysqli_query（）函數時沒有提供連接變量。

mysqli_query (mysqli $link , string $query)

作爲每PHP參考：

鏈路：只有程序式：）由mysqli_connect（）或mysqli_init（返回的鏈路標識符

查詢：查詢字符串。

http://php.net/manual/en/mysqli.query.php

來源

2017-06-14 10:42:11 Sehdev

<?php 
// you should connect the database 
$servername = "localhost"; 
$username = "username"; 
$password = "password"; 
$dbname = "myDB"; 

// Create connection 
$conn = new mysqli($servername, $username, $password, $dbname); 
// Check connection 
if ($conn->connect_error) { 
    die("Connection failed: " . $conn->connect_error); 
} 
$sql=mysqli_query("SELECT RoomTypeId from roomtypemaster"); 
$result = $conn->query($sql); 
//after this you will check the number of rows from your database table 
$count = mysqli_num_rows(); 
if($count>0){ 
    echo '<select>'; 
    while($data = $result->mysql_fetch_aasoc()){ 
    echo '<option value="'.$data['RoomTypeId'].'">'.$data['RoomTypeId'].'</option>'; 
    } 
    echo '</select>'; 
} 
?>

來源

2017-06-14 10:56:34

如何從DATABSE獲得價值並將其設置在PHP

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