如何在Doctrine 2中設置日期？

Question

我在學說實體中有一個名爲「生日」的字段。

我想創建一個對象來添加到數據庫使用原則。

控制器內部：

$name = "John Alex"; 
$birthday = "11-11-90"; 
$student = new Student(); 
$student->setName($name); 
$student->setBirthday(strtotime($birthday); 
... 

但是當我試圖堅持我得到這個錯誤

Fatal error: Call to a member function format() on a non-object in /Library/WebServer/Documents/Symfony/vendor/doctrine-dbal/lib/Doctrine/DBAL/Types/DateType.php on line 44 

編輯：

我的實體：

/** 
* @var string $name 
* 
* @ORM\Column(name="name", type="string", length=255) 
*/ 
private $name; 

/** 
* @var date $birthday 
* 
* @ORM\Column(name="birthday", type="date", nullable=true) 
*/ 
private $birthday; 

/** 
* Set birthday 
* 
* @param date $birthday 
*/ 
public function setBirthday($birthday) 
{ 
    $this->birthday = $birthday; 
} 

/** 
* Get birthday 
* 
* @return date 
*/ 
public function getBirthday() 
{ 
    return $this->birthday; 
} 

Answer 1

$name = "John Alex"; 
$birthday = "11-11-1990"; // I changed this 
$student = new Student(); 
$student->setName($name); 
$student->setBirthday(new \DateTime($birthday)); // setting a new date instance 
// ... 

Answer 2

您實體字段映射爲"datetime"或"date"應包含DateTime實例。

因此，你的二傳手應該是類型暗示如下：

/** 
* Set birthday 
* 
* @param \DateTime|null $birthday 
*/ 
public function setBirthday(\DateTime $birthday = null) 
{ 
    $this->birthday = $birthday ? clone $birthday : null; 
} 

/** 
* Get birthday 
* 
* @return \DateTime|null 
*/ 
public function getBirthday() 
{ 
    return $this->birthday ? clone $this->birthday : null; 
} 

這允許設置任何null或生日的的DateTime實例。如您注意，我也clone生日的值，以避免破壞封裝（見Doctrine2 ORM does not save changes to a DateTime field）。

要設置的生日，你後來乾脆以下：

$student->setBirthday(new \DateTime('11-11-90'));