我覺得你的問題有意思。我認爲答案可能對許多其他人有幫助。所以我寫了兩個演示，演示如何實現這些需求。
The first demo是從my previous answer哪些代碼您使用你的問題的文本已經使用的演示（這是基於在another one）基地。我還添加了the answer的技巧，以隱藏沒有子網格的行的子網格圖標（「+」）。
爲了簡化子網格數據的保持我在每一行subgrid屬性哪個值都爲次網格的數據添加。持有數據的類型非常實用，因爲jqGrid保存行的全部項目，因此您不需要更多隱藏列。要訪問本地數據，我建議使用getLocalRow方法。見the answer例如用於附加信息或getLocalRow方法，該方法是非常簡單的the source code。
第一演示代碼：
var myData = [
// main grid data
{ id: "m1", col1: "11", col2: "12",
subgrid: [
// data for subgrid for the id=m1
{ id: "s1a", c1: "aa", c2: "ab", c3: "ac",
subgrid: [
// data for subgrid for the id=m1, subgridId=s1a
{ id: "2s1a", d1: "2aa", d2: "2ab", d3: "2ac" },
{ id: "2s1b", d1: "2ba", d2: "2bb", d3: "2bc" },
{ id: "2s1c", d1: "2ca", d2: "2cb", d3: "2cc" }
]},
{ id: "s1b", c1: "ba", c2: "bb", c3: "bc" },
{ id: "s1c", c1: "ca", c2: "cb", c3: "cc" }
]},
{ id: "m2", col1: "21", col2: "22",
subgrid: [
// data for subgrid for the id=m2
{ id: "s2a", c1: "xx", c2: "xy", c3: "xz",
subgrid: [
// data for subgrid for the id=m2, subgridId=s2a
{ id: "2s2a", d1: "xx", d2: "xy", d3: "xz" }
]}
]},
{ id: "m3", col1: "31", col2: "32" }
],
removeSubgridIcon = function() {
var $this = $(this);
$this.find(">tbody>tr.jqgrow>td.ui-sgcollapsed").filter(function() {
var rowData = $this.jqGrid("getLocalRow",
$(this).closest("tr.jqgrow").attr("id"));
return rowData.subgrid == null;
}).unbind("click").html("");
},
isHasSubrids = function (data) {
var l = data.length, i;
for (i = 0; i < l; i++) {
if (data[i].subgrid != null) {
return true;
}
}
return false;
};
$("#list").jqGrid({
datatype: "local",
data: myData,
colNames: ["Column 1", "Column 2"],
colModel: [
{ name: "col1", width: 200 },
{ name: "col2", width: 200 }
],
gridview: true,
rownumbers: true,
autoencode: true,
sortname: "col1",
sortorder: "desc",
height: "100%",
pager: "#pager",
caption: "Demonstrate how to create subgrid from local hierarchical data",
subGrid: isHasSubrids(myData),
loadComplete: function() {
removeSubgridIcon.call(this);
},
subGridRowExpanded: function (subgridDivId1, rowId1) {
var $subgrid1 = $("<table id='" + subgridDivId1 + "_t'></table>"),
localRowData1 = $(this).jqGrid("getLocalRow", rowId1);
$subgrid1.appendTo("#" + $.jgrid.jqID(subgridDivId1));
$subgrid1.jqGrid({
datatype: "local",
data: localRowData1.subgrid,
colNames: ["Colunm1", "Colunm2", "Colunm3"],
colModel: [
{ name: "c1", width: 112 },
{ name: "c2", width: 112 },
{ name: "c3", width: 112 }
],
gridview: true,
rownumbers: true,
autoencode: true,
sortname: "c1",
sortorder: "desc",
height: "100%",
loadComplete: removeSubgridIcon,
subGrid: isHasSubrids(localRowData1.subgrid),
subGridRowExpanded: function (subgridDivId2, rowId2) {
var $subgrid2 = $("<table id='" + subgridDivId2 + "_t'></table>"),
localRowData2 = $(this).jqGrid("getLocalRow", rowId2);
$subgrid2.appendTo("#" + $.jgrid.jqID(subgridDivId2));
$subgrid2.jqGrid({
datatype: "local",
data: localRowData2.subgrid,
colNames: ["Col 1", "Col 2", "Col 3"],
colModel: [
{ name: "d1", width: 90 },
{ name: "d2", width: 90 },
{ name: "d3", width: 90 }
],
gridview: true,
rownumbers: true,
autoencode: true,
sortname: "d1",
sortorder: "desc",
height: "100%",
subGrid: isHasSubrids(localRowData2.subgrid),
loadComplete: removeSubgridIcon
});
}
});
}
});
The second demo是以前的演示更加深了修改。它可以用於創建非常深的多級子網格。我在演示中額外使用了密集的idPrefix來簡化使用ID的工作。我建議比較myData陣列中id屬性在第一個演示和第二個演示中的值。第二個演示代碼如下
var myData = [
// main grid data
{ id: "1", col1: "11", col2: "12",
subgrid: [
// data for subgrid for the id=m1
{ id: "1", c1: "aa", c2: "ab", c3: "ac",
subgrid: [
// data for subgrid for the id=m1, subgridId=s1a
{ id: "1", d1: "2aa", d2: "2ab", d3: "2ac" },
{ id: "2", d1: "2ba", d2: "2bb", d3: "2bc" },
{ id: "3", d1: "2ca", d2: "2cb", d3: "2cc" }
]},
{ id: "2", c1: "ba", c2: "bb", c3: "bc" },
{ id: "3", c1: "ca", c2: "cb", c3: "cc" }
]},
{ id: "2", col1: "21", col2: "22",
subgrid: [
// data for subgrid for the id=m2
{ id: "1", c1: "1xx", c2: "1xy", c3: "1xz",
subgrid: [
// data for subgrid for the id=m2, subgridId=s2a
{ id: "1", d1: "2xx", d2: "2xy", d3: "2xz" }
]}
]},
{ id: "3", col1: "31", col2: "32" }
],
removeSubgridIcon = function() {
var $this = $(this),
idPrefix = $this.jqGrid("getGridParam", "idPrefix");
$this.find(">tbody>tr.jqgrow>td.ui-sgcollapsed").filter(function() {
var rowData = $this.jqGrid("getLocalRow",
$.jgrid.stripPref(idPrefix, $(this).closest("tr.jqgrow").attr("id")));
return rowData.subgrid == null;
}).unbind("click").html("");
},
isHasSubrids = function (data) {
var l = data.length, i;
for (i = 0; i < l; i++) {
if (data[i].subgrid != null) {
return true;
}
}
return false;
},
specificGridOptions = [
{
colNames: ["Column 1", "Column 2"],
colModel: [
{ name: "col1" },
{ name: "col2" }
],
cmTemplate: { width: 200 },
sortname: "col1",
sortorder: "desc",
idPrefix: "s_",
pager: "#pager",
caption: "Demonstrate how to create subgrid from local hierarchical data"
},
{
colNames: ["Colunm1", "Colunm2", "Colunm3"],
colModel: [
{ name: "c1" },
{ name: "c2" },
{ name: "c3" }
],
cmTemplate: { width: 112 },
sortname: "c1",
sortorder: "desc"
},
{
colNames: ["Col 1", "Col 2", "Col 3"],
colModel: [
{ name: "d1" },
{ name: "d2" },
{ name: "d3" }
],
cmTemplate: { width: 90 },
sortname: "d1",
sortorder: "desc"
}
],
commonGridOptions = {
datatype: "local",
gridview: true,
rownumbers: true,
autoencode: true,
height: "100%",
loadComplete: function() {
// one can use loadComplete: removeSubgridIcon, but I included
// curent implementation of loadComplete only to show how to call
// removeSubgridIcon from your loadComplete callback handler
removeSubgridIcon.call(this);
},
subGridRowExpanded: function (subgridDivId, rowId) {
var $subgrid = $("<table id='" + subgridDivId + "_t'></table>"),
subgridLevel = $(this).jqGrid("getGridParam", "subgridLevel") + 1,
parentIdPrefix = $(this).jqGrid("getGridParam", "idPrefix"),
pureRowId = $.jgrid.stripPref(parentIdPrefix, rowId),
localRowData = $(this).jqGrid("getLocalRow", pureRowId);
$subgrid.appendTo("#" + $.jgrid.jqID(subgridDivId));
$subgrid.jqGrid($.extend(true, {}, commonGridOptions, specificGridOptions[subgridLevel], {
data: localRowData.subgrid,
subGrid: isHasSubrids(localRowData.subgrid),
subgridLevel: subgridLevel,
idPrefix: rowId + "_",
rowNum: 10000 // we use this to have no pager in the subgrids
}));
}
};
$("#list").jqGrid($.extend(true, {}, commonGridOptions, specificGridOptions[0], {
data: myData,
subgridLevel: 0,
subGrid: isHasSubrids(myData)
}));
感謝Oleg，很棒的解決方案！直到看到這個，我開始失去希望。這正是我正在尋找的。保持良好的工作。 （我試圖投票作爲答案，但我沒有足夠的聲望點。） –
@JonL：不客氣！這不是一個問題。如果你[[接受]]（http://meta.stackexchange.com/a/5235/147495）我的回答，你會得到3個額外的聲望點。獲得15個聲望點後，您將有權每天投票30個問題或答案**。你第一個問題非常有趣。可能你會像我一樣喜歡stakoverflow。最好的祝願！ – Oleg
我們如何可以編輯的第一張demo的所有單元格@oleg – neverwinter