不同的行與Rails的存儲陣列參數連接表

在軌道4應用隨着has_many :through關係不同的行與Rails的存儲陣列參數連接表

city.rb

has_many :business_type_cities 
has_many :business_types, :through => :business_type_cities

business_type.rb

has_many :business_type_cities 
has_many :cities, :through => :business_type_cities

businesstypecity .rb

belongs_to :buness_types 
belongs_to :cities

business_types_controller.rb

def create 
    if business_type.save 
    BusinessTypeCity.create :business_type_id => business_type.id,  :city_id => params[:cities] 
    flash[:notice] = 'Business Type Created Successfully!' 
    redirect_to admin_business_types_path 
    else 
    flash[:error] = business_type.errors.full_messages.join(', ') 
    end 
end

但這裏city_id是array，我想存儲business_type_id和city_id一行，其他city_id將不同行中存儲與同business_type_id。

響應我得到的是以下幾點：

"business_type"=>{"name"=>"test", "review_type"=>"review_with_rating"}, "cities"=>["293", "1091", "1200"], "commit"=>"Create Business Type"

感謝

來源

2016-08-23 urjit on rails

簡單，我需要迭代PARAMS [：城市]與每個做。雖然如果你有更好的答案，那麼對此感興趣。感謝您的時間。 –

通常的做法是，你在評論所說的東西。以下是我通常所做的

existing_city_ids = business_type.city_ids 
business_type.city_ids = existing_city_ids | params[:cities].map(&:to_i)

首先獲取當前業務類型的所有現有城市id。然後結合新的，使用||以避免重複，並將params[:cities]映射到int以匹配business_type.city_ids (returns an array of int)

來源

2016-08-23 08:00:15 lusketeer

不同的行與Rails的存儲陣列參數連接表

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