Bootstrap Tabpanel Next Previous按鈕

Question

我有一個Tab Tab，它有很長的內容，所以用戶有下一個和上一個按鈕會更好。

但他們不工作。

這是ASPX代碼：

<div class="col_4"> 
<div class="bs-example bs-example-tabs" role="tabpanel" data-example-id="togglable-tabs"> 
    <ul id="myTab" class="nav nav-tabs nav-tabs1" role="tablist"> 
     <li role="presentation" class="active"><a href="#aboutmyself" id="aboutmyself-tab" role="tab" data-toggle="tab" aria-controls="aboutmyself" aria-expanded="true">About Myself</a></li> 
     <li role="presentation"><a href="#familydetails" role="tab" id="familydetails-tab" data-toggle="tab" aria-controls="familydetails">Family Details</a></li> 
     <li role="presentation"><a href="#partnerpreference" role="tab" id="partnerpreference-tab" data-toggle="tab" aria-controls="partnerpreference">Partner Preference</a></li> 
     <li role="presentation"><a href="#contact" role="tab" id="contact-tab" data-toggle="tab" aria-controls="contact">Contact</a></li> 
    </ul> 
    <div id="myTabContent" class="tab-content"> 
     <div role="tabpanel" class="tab-pane fade in active" id="aboutmyself" aria-labelledby="aboutmyself-tab"> 
      <!--Tab1 content--> 
      <a class="btn-all btnNext" >Next</a> 
     </div> 
     <div role="tabpanel" class="tab-pane fade" id="familydetails" aria-labelledby="familydetails-tab"> 
      <!--Tab2 content--> 
      <a class="btn-all btnPrevious" >Previous</a> 
      <a class="btn-all btnNext" >Next</a> 
     </div> 
     <div role="tabpanel" class="tab-pane fade" id="partnerpreference" aria-labelledby="partnerpreference-tab"> 
      <!--Tab3 content--> 
      <a class="btn-all btnPrevious" >Previous</a> 
      <a class="btn-all btnNext" >Next</a> 
     </div> 
     <div role="tabpanel" class="tab-pane fade" id="contact" aria-labelledby="contact-tab"> 
      <!--Tab4 content--> 
      <a class="btn-all btnPrevious" >Previous</a> 
     </div> 

這裏是腳本。

<script type="text/javascript"> 
    $('.btnNext').click(function() { 
     $('.nav-tabs > .active').next('li').find('a').trigger('click'); 
    }); 

    $('.btnPrevious').click(function() { 
     $('.nav-tabs > .active').prev('li').find('a').trigger('click'); 
    }); 
</script> 

Answer 1

Working fiddle

你的代碼工作正常，你應該只是把它裏面ready功能：

$(function(){ 
    $('.btnNext').click(function() { 
     $('.nav-tabs > .active').next('li').find('a').trigger('click'); 
    }); 

    $('.btnPrevious').click(function() { 
     $('.nav-tabs > .active').prev('li').find('a').trigger('click'); 
    }); 
}) 

希望這有助於。