我在非對象上調用成員函數close（）時收到致命錯誤

Question

這是更新表中字段值的腳本。查詢後，我得到的錯誤：

Fatal error: Call to a member function close() on a non-object

<?php 
    error_reporting(E_ALL);ini_set('display_errors','On'); 

    define('DB_HOST', 'xxxxxx'); 
    define('DB_NAME', 'xxxxxx'); 
    define('DB_USER','xxxxxx'); 
    define('DB_PASSWORD','xxxxxxx'); 

    $mysqli = new mysqli(DB_HOST, DB_USER, DB_PASSWORD, DB_NAME) or die("Failed to connect to MySQL: " . mysqli_error()); 

    if ($mysqli->connect_errno) { 
     echo "Failed to connect to MySQL: (" . $mysqli->connect_errno . ") " . $mysqli->connect_error; 
    } 

    $result = $mysqli->query("update people_table set FirstName = 'Jon' where LastName = 'Smith'") or die($mysqli->error); 
    $result->close(); 

    ?> 

$結果是一個對象，我的看法這混淆了我

Answer 1

我覺得這是你需要編寫，而不是結果對象是什麼

$mysqli->close();