Mysql - 特定日期的特定列

Question

我有一個數據庫，記錄每個收銀員每小時的交易次數。

列名：

NAME  00 01 02 03 04 05 06 07 08 09 10 11 12 13 14 15 16 17 18 19 20 21 22 23 DATE 

00是午夜，01是凌晨1點，18是下午6點等。

的平均行應該是這樣的：

John Doe 0 0 0 0 0 0 0 0 0 0 26 24 32 0 0 0 0 0 0 0 0 0 0 0 02/23/2014 
    John Doe 0 0 0 0 0 23 43 25 36 42 0 0 0 0 0 0 0 0 0 0 0 0 0 0 02/22/2014 

我試圖獲得相同的查詢從不同的日子不同的列。

例如，假設我想從2014年2月22日開始的05,06,07,08,09和2014年2月23日開始的10,11,12期間爲John Doe。這將是John Doe整個週末的總小時交易。

假設John Doe本月大部分時間都有排。我怎樣才能得到一條只顯示2014年2月22日的05,06,07,08和09小時以及2014年2月23日的10,11,12小時，而沒有其他日期/小時的線路？

我嘗試這樣做：

SELECT cashier.name AS NAME, 
(SELECT cashier.05 FROM cashier AS t WHERE date = '2014-02-22' AND t.name = cashier.name) as '05', 
(SELECT cashier.06 FROM cashier AS t WHERE date = '2014-02-22' AND t.name = cashier.name) as '06', 
(SELECT cashier.07 FROM cashier AS t WHERE date = '2014-02-22' AND t.name = cashier.name) as '07', 
(SELECT cashier.08 FROM cashier AS t WHERE date = '2014-02-22' AND t.name = cashier.name) as '08', 
(SELECT cashier.09 FROM cashier AS t WHERE date = '2014-02-22' AND t.name = cashier.name) as '09', 
(SELECT cashier.10 FROM cashier AS t WHERE date = '2014-02-23' AND t.name = cashier.name) as '10', 
(SELECT cashier.11 FROM cashier AS t WHERE date = '2014-02-23' AND t.name = cashier.name) as '11', 
(SELECT cashier.12 FROM cashier AS t WHERE date = '2014-02-23' AND t.name = cashier.name) as '12' 
FROM cashier 
WHERE NAME = 'John Doe' 

Answer 1

SELECT f.name , f.17, 
(SELECT t.05 FROM cashier AS t WHERE f.name = t.name AND t.date = '2014-02-22') AS '05', 
(SELECT t.06 FROM cashier AS t WHERE f.name = t.name AND t.date = '2014-02-22') AS '06', 
(SELECT t.07 FROM cashier AS t WHERE f.name = t.name AND t.date = '2014-02-22') AS '07', 
(SELECT t.08 FROM cashier AS t WHERE f.name = t.name AND t.date = '2014-02-22') AS '08', 
(SELECT t.09 FROM cashier AS t WHERE f.name = t.name AND t.date = '2014-02-22') AS '09', 
(SELECT t.10 FROM cashier AS t WHERE f.name = t.name AND t.date = '2014-02-23') AS '10', 
(SELECT t.11 FROM cashier AS t WHERE f.name = t.name AND t.date = '2014-02-23') AS '11', 
(SELECT t.12 FROM cashier AS t WHERE f.name = t.name AND t.date = '2014-02-23') AS '12' 
FROM cashier AS f 
WHERE date = '2014-02-22' 
AND f.18 > 0");