ASMX返回XML數據:如何讀取Web服務在JQuery中
public class ItemRecord
{
public string model { get;set; }
public string verzia { get;set; }
public string typ { get;set; }
public string motor { get;set; }
}
[WebMethod]
public ItemRecord GetRecord(int id)
{
ItemRecord record = new ItemRecord();
using (SqlConnection sConnection = new SqlConnection(ConfigurationManager.ConnectionStrings["bazarovkyConnectionString"].ToString()))
{
sConnection.Open();
SqlCommand sCommand = sConnection.CreateCommand();
sCommand.CommandText = "select id_model, motor from data_motorizacia where [email protected]";
sCommand.Parameters.AddWithValue("@id", id);
SqlDataReader sReader = sCommand.ExecuteReader();
if (sReader.Read())
{
record.model = sReader["id_model"].ToString();
record.motor = sReader["motor"].ToString();
}
}
return record;
}
JQUERY:
id = $("#view_id", row).text();
$.ajax({
type: "POST",
url: "/data.asmx/GetRecord",
data: "{'id':'" + id + "'}",
contentType: "application/json; charset=utf-8",
dataType: "xml",
processData: false,
error: function (XMLHttpRequest, textStatus, errorThrown) { ajaxError(XMLHttpRequest, textStatus, errorThrown); },
success: function (xml) { ajaxFinish(xml); }
});
function ajaxFinish(xml) {
// parse the object
alert($(xml).find("motor").text());
}
我想要做的是讀電機和id_model在ajaxFinish的價值。但是它要麼返回對象(如果我只指向XML)或者未指定或空的。
如何跟蹤/調試.ASMX文件返回的內容?
但我想返回值,而不是在.ASMX文件中生成完整的HTML代碼。 – feronovak 2011-02-28 08:16:56
您不需要在asmx中生成完整的HTML代碼。只需從webservice返回json而不是xml。 – 2011-02-28 08:18:27