C＃Windows窗體 - 選擇並複製多個文件有多重選擇，打開文件對話框，與FileBrowserDialog

Question

我正在開發使用C＃與一個OpenFileDialog和FileBrowserDialog一個WinForms應用程序，我想：

1. 啓用多重選擇xls文件。
2. 選擇後作出，
3. 複製選定的文件顯示所選的xlsx文件名的文本框合併一個單獨的目錄

我怎樣才能做到這一點？

Answer 1

下面是示例代碼：

 OpenFileDialog od = new OpenFileDialog(); 
     od.Filter = "XLS files|*.xls"; 
     od.Multiselect = true; 
     if (od.ShowDialog() == System.Windows.Forms.DialogResult.OK) 
     { 
      string tempFolder = System.IO.Path.GetTempPath(); 

      foreach (string fileName in od.FileNames) 
      { 
       System.IO.File.Copy(fileName, tempFolder + @"\" + System.IO.Path.GetFileName(fileName)); 
      } 
     } 

Answer 2

有OpenFileDialog的MultiSelect屬性，您需要將其設置爲true以允許選擇多個文件。

從MSDN Here is a code example，其允許用戶選擇圖像的倍數數目，並顯示它們在圖片框窗體上的控件：

private void Form1_Load(object sender, EventArgs e) 
{ 
    InitializeOpenFileDialog(); 
} 

private void InitializeOpenFileDialog() 
{ 
    // Set the file dialog to filter for graphics files. 
    this.openFileDialog1.Filter = 
    "Images (*.BMP;*.JPG;*.GIF)|*.BMP;*.JPG;*.GIF|" + 
    "All files (*.*)|*.*"; 

    // Allow the user to select multiple images. 
    this.openFileDialog1.Multiselect = true; 
    this.openFileDialog1.Title = "My Image Browser"; 
} 

private void selectFilesButton_Click(object sender, EventArgs e) 
{ 
    DialogResult dr = this.openFileDialog1.ShowDialog(); 
    if (dr == System.Windows.Forms.DialogResult.OK) 
    { 
    // Read the files 
    foreach (String file in openFileDialog1.FileNames) 
    { 
     // Create a PictureBox. 
     try 
     { 
      PictureBox pb = new PictureBox(); 
      Image loadedImage = Image.FromFile(file); 
      pb.Height = loadedImage.Height; 
      pb.Width = loadedImage.Width; 
      pb.Image = loadedImage; 
      flowLayoutPanel1.Controls.Add(pb); 
     } 
     catch (SecurityException ex) 
     { 
      // The user lacks appropriate permissions to read files, discover paths, etc. 
      MessageBox.Show("Security error. Please contact your administrator for details.\n\n" + 
       "Error message: " + ex.Message + "\n\n" + 
       "Details (send to Support):\n\n" + ex.StackTrace 
      ); 
     } 
     catch (Exception ex) 
     { 
      // Could not load the image - probably related to Windows file system permissions. 
      MessageBox.Show("Cannot display the image: " + file.Substring(file.LastIndexOf('\\')) 
       + ". You may not have permission to read the file, or " + 
       "it may be corrupt.\n\nReported error: " + ex.Message); 
     } 
    } 
} 

Answer 3

結合兩個答案，這是我想出的代碼：

• 啓用用戶到選擇多個XLSX檔案（多選使用，打開文件對話框，this.OpenFileDialog屬性& FileBrowserDialog）
• 選擇後製成，顯示在文本框選擇XLSX文件名（通過設置textBoxSourceFiles.Text值sourceFileOpenFileDialog.FileNames）

• 複製所選文件到一個單獨的綜合目錄（使用foreach循環，System.IO.File.Copy，System.IO.Path.GetFileName，sourceFileOpenFileDialog.FileName）

  private void sourceFiles_Click(object sender, EventArgs e) 
  { 
      Stream myStream; 
      OpenFileDialog sourceFileOpenFileDialog = new OpenFileDialog(); 
  
      this.sourceFileOpenFileDialog.InitialDirectory = "i:\\CommissisionReconciliation\\Review\\"; 
      this.sourceFileOpenFileDialog.Filter = "Excel Files (*.xls;*.xlsx;)|*.xls;*.xlsx;|All Files (*.*)|*.*"; 
      this.sourceFileOpenFileDialog.FilterIndex = 2; 
      this.sourceFileOpenFileDialog.RestoreDirectory = true; 
      this.sourceFileOpenFileDialog.Multiselect = true; 
      this.sourceFileOpenFileDialog.Title = "Please Select Excel Source File(s) for Consolidation"; 
  
      if (sourceFileOpenFileDialog.ShowDialog() == DialogResult.OK) 
      { 
       try 
       { 
        if ((myStream = sourceFileOpenFileDialog.OpenFile()) != null) 
        { 
         using (myStream) 
         { 
          // populates text box with selected filenames 
          textBoxSourceFiles.Text = sourceFileOpenFileDialog.FileNames; 
         } 
        }  // ends if 
       }   // ends try 
  
       catch (Exception ex) 
       { 
        MessageBox.Show("Error: Could not read file from disk. Original error: " + ex.Message); 
       } 
      }    // ends if (sourceFileOpenFileDialog.ShowDialog() == DialogResult.OK) 
  }     // ends public void sourceFiles_Click 
  
  private void consolidateButton_Execute_Click(object sender, EventArgs e) 
  { 
  
      string consolidatedFolder = targetFolderBrowserDialog.SelectedPath; 
  
       foreach (String file in sourceFileOpenFileDialog.FileNames) 
       { 
        try 
        { 
         // Copy each selected xlsx files into the specified TargetFolder 
  
         System.IO.File.Copy(sourceFileOpenFileDialog.FileName, consolidatedFolder + @"\" + System.IO.Path.GetFileName(sourceFileOpenFileDialog.FileName)); 
         Log("File" + sourceFileOpenFileDialog.FileName + " has been copied to " + consolidatedFolder + @"\" + System.IO.Path.GetFileName(sourceFileOpenFileDialog.FileName)); 
        } 
       }   // ends foreach loop 
  }     // ends void consolidateButton_Execute_Click