0
這是php代碼,這裏我要求離子3的用戶名和密碼做一個select查詢如果我的sql中有數據,我會返回到離子3接受,如果沒有,拒絕這是登錄頁面。我在離子3中遇到了一個錯誤:運行時錯誤意外的標記<在位置0的JSON中發佈到來自ionic3的php時
$Username= filter_var($_REQUEST['Username'], FILTER_SANITIZE_STRING, FILTER_FLAG_ENCODE_LOW);
$Password = filter_var($_REQUEST['Password'], FILTER_SANITIZE_STRING, FILTER_FLAG_ENCODE_LOW);
$sql="SELECT Username, Password FROM doctoradd WHERE Username = :Username AND Password = :Password";
//$sql = "INSERT INTO technologies(name, description) VALUES(:Username, :Password)";
$stmt = $pdo->prepare($sql);
$stmt->bindParam(':Username', $Username, PDO::PARAM_STR);
$stmt->bindParam(':Password', $Password, PDO::PARAM_STR);
$stmt->execute();
while($row = $stmt->fetch(PDO::FETCH_OBJ))
{
// Assign each row of data to associative array
$data[] = $row;
}
if($data == []){
echo json_encode("null");
}
else{
echo json_encode("accepted");
}
我離子3碼:這是按鈕點擊功能
let Username : string = this.form.controls["Username"].value,
Password : string = this.form.controls["Password"].value;
let body : string = "Username=" + Username + "&Password=" + Password,
type : string = "application/x-www-form-urlencoded; charset=UTF-8",
headers : any = new Headers({ 'Content-Type': type}),
options : any = new RequestOptions({ headers: headers }),
url : any = this.baseURI + "sign-in.php";
this.http.post(url, body, options)
.subscribe((data) =>
{
// If the request was successful notify the user
// if(data.status === 200)
// {
// //this.hideForm = true;
// this.toast.create({
// message: 'Welcome ',
// duration:3000
// }).present();
// //this.sendNotification(`Congratulations the technology: ${username} was successfully added`);
// }
// // Otherwise let 'em know anyway
// else
// {
// //this.sendNotification('Something went wrong!');
// this.toast.create({
// message: 'Wrong Username or Password',
// duration:3000
// }).present();
// }
});
this.SignIn();
}
的登入功能,我想取回json_encode在PHP如果被接受與否
SignIn(){
this.http.get('http://localhost:10080/testdb/sign-in.php')
.map(res => res.json())
.subscribe(data =>
{
this.items = data;
});
alert(this.items);
if(this.items=="accepted"){
this.navCtrl.push('ExamplePage',this.username);
}
else{
this.toast.create({
message: 'Wrong Username or Password',
duration:3000
}).present();
}
}
我只是刪除了.MAP並停止給我,但「this.items」點擊按鈕,但兩個輸入值是在數據庫中,你可以幫我這個當是給一個空值的錯誤! !謝謝你 –
你可以控制檯登錄你的回覆併發送給我嗎? –
console.log(res)發生錯誤:無法找到名稱'res'。我可以在沒有.map的情況下使用它嗎?我用它沒有它,但this.items按鈕點擊賦予空值,你可以幫助這個? –