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我想了解使用Struts2,Hibernate和EJB的JavaEE體系結構的基本體系結構。Hibernate EJB體系結構 - 模型ClassNotFoundException
我有一個簡單的應用程序,添加員工並列出他們。
到目前爲止,我已經在Eclipse中取得3個項目:
- JPA項目,該項目包含了我的模型鏈接到數據庫
- EJB項目,該項目處理服務層
- 動態Web項目對Struts 2
動態Web項目> controller.EmployeeAction.java:
import local.EmployeeService;
import model.Employee;
public class EmployeeAction extends ActionSupport {
private Employee employee;
private Collection<Employee> employeeList;
@EJB
private EmployeeService employeeManager;
public String execute() {
this.employeeList = employeeManager.findAll();
return SUCCESS;
}
public String add() {
employeeManager.addItem(this.employee);
this.employeeList = employeeManager.findAll();
return SUCCESS;
}
[...]
}
EJB項目> local.EmployeeService.java:
import model.Employee;
@Stateless
public class EmployeeService {
@PersistenceContext
private EntityManager em;
public void addItem(Employee i) {
em.persist(i);
}
public Collection<Employee> findAll() {
Query query = em.createQuery("SELECT e FROM Employee e");
return (Collection<Employee>) query.getResultList();
}
}
JPA項目> model.Employee:
@Entity
@Table(name="\"Employee\"")
@NamedQuery(name="Employee.findAll", query="SELECT e FROM Employee e")
public class Employee implements Serializable {
private static final long serialVersionUID = 1L;
@Id
@Column(unique=true, nullable=false)
private Integer idemployee;
@Column(length=255)
private String password;
@Column(nullable=false, length=255)
private String username;
public Employee() {
}
public Integer getIdemployee() {
return this.idemployee;
}
public void setIdemployee(Integer idemployee) {
this.idemployee = idemployee;
}
[...]
}
但是當我嘗試添加僱員,我得到model.Employee
一個ClassNotFoundException。
類路徑看起來不錯。我錯過了什麼嗎?
謝謝,我有另一個問題,但是這個問題已經修復。請注意,它在Eclipse Kepler中被稱爲'Deployment Assembly'。 – Arthur