總結新線過長的字符串輸出在bash

Question

想象一下你的腳本輸出像一些真正奇怪的輸出：

fdjsagnfafeowkagfdsngodagfoeagnfiosnthoaogjerapogrjeagnfdosngtnsrhig ofskhnIAGNRIEAGPREAOGJRIAEGRNIEOASGNFAIGRNESUIGRIOAEGRNIAENGRUEAOREANFDOIGNRUESIGORNAEIGNREIOAGRIUESGRJOEAGRNEOSIGRNEPAGRJAEIO 

廢話，我知道。也許這樣看起來會更好：

fdjsagnfafeowkagfdsngodagfoeagnfiosnthoaogjera 
pogrjeagnfdosngtnsrhig ofskhnIAGNRIEAGPREAOGJR 
IAEGRNIEOASGNFAIGRNESUIGRIOAEGRNIAENGRUEAOREAN 
FDOIGNRUESIGORNAEIGNREIOAGRIUESGRJOEAGRNEOSIGR 
NEPAGRJAEIO 

我想在bash中用base64編碼的字符串數據做到這一點。我怎麼能這樣做？

Answer 1

對於您的示例輸入，fold將生成您請求的輸出。假設我們有這樣的文件：

$ cat longline 
fdjsagnfafeowkagfdsngodagfoeagnfiosnthoaogjerapogrjeagnfdosngtnsrhig ofskhnIAGNRIEAGPREAOGJRIAEGRNIEOASGNFAIGRNESUIGRIOAEGRNIAENGRUEAOREANFDOIGNRUESIGORNAEIGNREIOAGRIUESGRJOEAGRNEOSIGRNEPAGRJAEIO 

爲了與寬度46個字符的行：

$ fold -w 46 longline 
fdjsagnfafeowkagfdsngodagfoeagnfiosnthoaogjera 
pogrjeagnfdosngtnsrhig ofskhnIAGNRIEAGPREAOGJR 
IAEGRNIEOASGNFAIGRNESUIGRIOAEGRNIAENGRUEAOREAN 
FDOIGNRUESIGORNAEIGNREIOAGRIUESGRJOEAGRNEOSIGR 
NEPAGRJAEIO 

如果你想在一個管道中使用它，fold也接受標準輸入：

$ fold -w 46 <longline 
fdjsagnfafeowkagfdsngodagfoeagnfiosnthoaogjera 
pogrjeagnfdosngtnsrhig ofskhnIAGNRIEAGPREAOGJR 
IAEGRNIEOASGNFAIGRNESUIGRIOAEGRNIAENGRUEAOREAN 
FDOIGNRUESIGORNAEIGNREIOAGRIUESGRJOEAGRNEOSIGR 
NEPAGRJAEIO 

在Linux上，fold是GNU coreutils的一部分，應默認安裝。它也可在Mac OSX下獲得。