每一次出現，但

Question

Basicly此代碼更復雜的給我< LI> 1 2 3 4 </LI> < LI> 1 2 3 4 </LI> < LI> 1 2 </LI>。所以基本上最後我需要把3和4換成不同的結果，例如，< li> 1 2空的空</li> - 因爲每個結果總是應該有4個結果< li> </li>，這很棘手，因爲循環給出儘可能多的東西，有時候會少一些:)。

<ul> 

{section name=attribs loop=$AccountHistory} 
    {if $smarty.section.attribs.index % 4 == 0 or $smarty.section.attribs.first} 
    <li> 
    {/if} 

     {$smarty.section.iteration} 

    {if $smarty.section.attribs.index % 4 == 3 or $smarty.section.attribs.last} 
    </li> 
    {/if} 

{/section} 

</ul> 

Answer 1

也許像這樣進入循環？

{if $smarty.section.attribs.last && ($smarty.section.attribs.index % 4) >0} 
    {section name=tmp loop=(4-($smarty.section.attribs.index % 4)) start=(($smarty.section.attribs.index % 4) + 1)} 
     {$smarty.section.tmp.index} 
    {/section} 
{/if}