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我正在使用JavaScript編寫一個rock-paper-scissors遊戲。我無法從用戶那裏獲取單選按鈕的輸入。如果機器人贏得了一輪比賽,那麼它也應該爲他的得分加1,而現在每次都是這樣。這裏是我試過的代碼:我試圖與for
循環,這是既沒有工作做檢索無法正常工作的收音機輸入
function playBot(){
var num = Math.floor((Math.random() * 4) + 1); // generate number between 1 and 3 which represents the item bot has chosen
console.log(num);
var rock = document.getElementById("rock").value;
var paper = document.getElementById("paper").value;
var scissors = document.getElementById("scissors").value;
var result = document.getElementById("result");
// 1 = rock, 2 = paper, 3 = scissors
if (rock.checked == true && num != 2){
pl1 = pl1 + 1;
document.getElementById("pl1").innerHTML = pl1;
} else if (paper.checked == true && num != 3){
pl1 = pl1 + 1;
document.getElementById("pl1").innerHTML = pl1;
} else if (scissors.checked == true && num != 1){
pl1 = pl1 + 1;
document.getElementById("pl1").innerHTML = pl1;
} else {
pl2 = pl2 + 1;
document.getElementById("pl2").innerHTML = pl2;
}
}
:
HTML:
<h2 id="score"><span id="pl1">0</span>-<span id="pl2">0</span></h2>
<div id="left">
<label for="rock">Rock</label><br>
<input type="radio" name="q" class="q" id="rock"></input><br>
<label for="paper">Paper</label><br>
<input type="radio" name="q" class="q" id="paper"></input><br>
<label for="scissors">Scissors</label><br>
<input type="radio" name="q" class="q" id="scissors"></input><br>
<button id="confirm" class="button" onClick="playBot()" style="margin-bottom: 10px;">Confirm</button>
</div><p id="result"></p>
和JavaScript 。來源我已經試過:How to get value of selected radio button?
Get Radio Button Value with Javascript
http://www.w3schools.com/jsref/prop_radio_checked.asp
在此先感謝
哇檢查值,感謝您的回答。不知道這是簡單的,它現在效果很好!再次感謝:) –
很高興我能幫忙!如果您點擊答案上的投票按鈕下方的複選標記,您可以將其列爲「已接受」;這將非常感激。 –
是的,我還沒有點擊它,不得不等待3分鐘 –