類型不匹配;找到：play.api.data.Form [controllers.Application.Userdata] required：play.api.data.Form [（String，String）]

Question

我創建了一個簡單的登錄提交表單使用playframework和scala，而無需連接任何數據庫。

我application.scala這是我的控制器我寫的代碼

import play.api._ 
import play.api.mvc._ 
import play.api.data._ 
import play.api.data.Forms._ 
import play.api.mvc.Request 
import views.html._ 

case class Userdata(email:String,password:String) 

object Application extends Controller { 

    case class Userdata(email:String,password:String) 

    val userForm = Form(
    mapping(
    "email" -> text, 
    "password" -> text 
)(Userdata.apply)(Userdata.unapply) 
) 

    def usercheck = Action{ implicit request=> 

    userForm.bindFromRequest.fold(
     formWithErrors => BadRequest(views.html.login(formWithErrors)), 
     Userdata => { Ok(views.html.index("congrates"))} 

    )} 
    def index() = Action { 
    implicit request=> 
    Ok(views.html.login(userForm)) 
    } 

和我的視圖模板是login.scala.html ..

@(form: Form[(String,String)]) 

@import helper._ 


    @form(routes.Application.usercheck){ 
    <form class=frmuuser> 
     <input type=text placeholder=email id='emailid'> 
     <input type=password placeholder=password id='pwd'> 
     <input type=submit value=login id='enter'> 

    </form> 
    } 

，但它不工作，並給了我錯誤

type mismatch; found : play.api.data.Form[controllers.Application.Userdata] required: play.api.data.Form[(String, String)] 

在這個控制器線

formWithErrors => BadRequest(views.html.login(formWithErrors)), 

什麼是靈魂我的問題??

Answer 1

幾點要注意：

• 把你的測試用例類Userdata應用控制器之外。這是將其移入控制器包內。
• 您也可以在模板的開頭添加@import，以導入任意包或類。

試試這個。

Application.scala：只有一個Userdata情況下，類定義（您有兩個定義這些類的）

import play.api._ 
import play.api.mvc._ 
import play.api.data._ 
import play.api.data.Forms._ 
import play.api.mvc.Request 
import views.html._ 

case class Userdata(email:String, password:String) 

object Application extends Controller { 

    val userForm = Form(
    mapping(
    "email" -> text, 
    "password" -> text 
)(Userdata.apply)(Userdata.unapply) 
) 

    def usercheck = Action{ implicit request=> 

    userForm.bindFromRequest.fold(
     formWithErrors => BadRequest(views.html.login(formWithErrors)), 
     Userdata => { Ok(views.html.index("congrates"))} 

    )} 
    def index() = Action { 
    implicit request=> 
    Ok(views.html.login(userForm)) 
    } 

login.scala.html：使用Userdata代替(String, String)

@(form: Form[Userdata]) 
@import helper._ 

    @form(routes.Application.usercheck){ 
    <form class=frmuuser> 
     <input type=text placeholder=email id='emailid'> 
     <input type=password placeholder=password id='pwd'> 
     <input type=submit value=login id='enter'> 

    </form> 
    }