0
我解析XML文件中的數據並將其放入數組中,然後將數據輸出到另一個函數中。創建Android ArrayList錯誤
private void parseXML(XmlPullParser parser) throws XmlPullParserException,IOException
{
ArrayList<String> animals = new ArrayList<String>();
int eventType = parser.getEventType();
Animal currentAnimal = null;
while (eventType != XmlPullParser.END_DOCUMENT)
{
String name = null;
switch (eventType)
{
case XmlPullParser.START_DOCUMENT:
//animals = new ArrayList();
break;
case XmlPullParser.START_TAG:
name = parser.getName();
if (name.equalsIgnoreCase("animal"))
{
currentAnimal = new Animal();
}
else if (currentAnimal != null)
{
if (name.equalsIgnoreCase("specificLocation"))
{
currentAnimal.specificLocation = parser.nextText();
}
else if (name .equalsIgnoreCase("name")){
currentAnimal.name = parser.nextText();
}
else if (name .equalsIgnoreCase("location"))
{
currentAnimal.location= parser.nextText();
}
else if (name .equalsIgnoreCase("image"))
{
currentAnimal.image= parser.nextText();
}
else if (name .equalsIgnoreCase( "animalInfo"))
{
currentAnimal.animalInfo= parser.nextText();
}
else if (name .equalsIgnoreCase( "todaysFeed"))
{
currentAnimal.todaysFeed= parser.nextText();
}
}
break;
case XmlPullParser.END_TAG:
name = parser.getName();
if (name.equalsIgnoreCase("animal") && currentAnimal != null){
animals.add(currentAnimal);
}
}
eventType = parser.next();
}
printAnimals(animals);
}
我在這告訴我
在ArrayList類型的方法添加(字符串)不適用於參數的線
animals.add(currentAnimal);
(AnimalList得到一個錯誤.Animal)
我本來有動物而不是字符串,但是我改了它一個我無法輸出它,我不確定這是爲什麼。
這就是我本來後來 – Navvy 2014-12-04 21:41:16
私人無效printAnimals(ArrayList的動物) \t { \t \t動物[] animalArray =新的動物[ animals.size()]; \t \t animalArray = animals.toArray(animalArray); \t \t ListView listView =(ListView)findViewById(R.id.listViewAnimals); \t \t ArrayAdapter animalAdapter = new ArrayAdapter (this,android.R.layout.simple_list_item_1,animals); \t \t listView.setAdapter(animalAdapter); \t}將無法正常工作 –
Navvy
2014-12-04 21:42:27
您的代碼很難在評論中閱讀... – EJK 2014-12-04 21:45:15