如何知道IOexception發生在文件的哪一行

Question

在我的程序中，我想從文本文件中讀取。我的文件中的數據是由空格分隔的數字。我會在我的程序中將它們轉換爲整數。如果從文件讀取的數據不是數字，我想捕獲異常。我想知道文件的哪一行發生了錯誤（數據不是數字）。我知道我應該趕上NumberFormatException異常，但不知道如何找到異常行。 這裏是一個代碼位：

try 
{ 
    //...using Bufferreader ...some code here 
    while ((strLine = br.readLine()) != null) 
    { 
    String[] term = strLine.split(" "); 
    //for now i just work with the first element of the array 
    int num = Integer.parseInt(term[0]); 
    //....some code here 
    } 
    in.close(); 
} 
catch (NumberFormatException eg) 
{ 
    System.out.println("Error: there is a problem in line ..? "); 
} 

Answer 1

int num = Integer.parseInt(term[0]); 

上面一行將拋出NumberFormatException的參數時不會號碼。

Answer 2

int line = 0; 
try 
{ 
    //...using Bufferreader ...some code here 
    while ((strLine = br.readLine()) != null) 
    { 
    line ++; 
    String[] term = strLine.split(" "); 
    //for now i just work with the first element of the array 
    int num = Integer.parseInt(term[0]); 
    //....some code here 
    } 
    in.close(); 
} 
catch (NumberFormatException eg) 
{ 
    System.out.println("Error: there is a problem in line " + line); 
}