zip文件內的pdfs被破壞

Question

我想製作一個包含pdf的zip文件。當我解壓縮zip時，pdf已損壞。我在'outputStream'上放置了一塊手錶。這是第一個例外

'outputStream.Length' 扔類型的異常的 'System.NotSupportedException' 長

這裏是整個鐘錶

代碼

[HttpPost] 
    [ActionName("ZipFileAction")] 
    public HttpResponseMessage ZipFiles([FromBody]int[] id) 
    { 
     if (id == null) 
     {//Required IDs were not provided 
      throw new HttpResponseException(new HttpResponseMessage(HttpStatusCode.BadRequest)); 
     } 

     List<Document> documents = new List<Document>(); 
     using (var context = new ApplicationDbContext()) 
     { 
      foreach (int NextDocument in id) 
      { 
       Document document = context.Documents.Find(NextDocument); 

       if (document == null) 
       { 
        throw new HttpResponseException(new HttpResponseMessage(HttpStatusCode.NotFound)); 
       } 

       documents.Add(document); 
      } 
      var streamContent = new PushStreamContent((outputStream, httpContext, transportContent) => 
      { 
       try 
       { 
        using (var zipFile = new ZipFile()) 
        { 
         foreach (var d in documents) 
         { 
          var dt = d.DocumentDate.ToString("y").Replace('/', '-').Replace(':', '-'); 
          string fileName = String.Format("{0}-{1}-{2}.pdf", dt, d.PipeName, d.LocationAb); 
          zipFile.AddEntry(fileName, d.DocumentUrl); 
         } 
         zipFile.Save(outputStream); //Null Reference Exception 
        } 
       } 

       finally 
       { 
        outputStream.Close(); 
       } 
      }); 
      streamContent.Headers.ContentType = new MediaTypeHeaderValue("application/octet-stream"); 
      streamContent.Headers.ContentDisposition = new ContentDispositionHeaderValue("attachment"); 
      streamContent.Headers.ContentDisposition.FileName = "reports.zip"; 

      var response = new HttpResponseMessage(HttpStatusCode.OK) 
      { 
       Content = streamContent 
      }; 
      return response; 
     } 

Answer 1

問題被證明是我沒有保存在PDF的任何內容。我只是保存documentUrl。所以通過使用FileInfo來改變事情。工作代碼

[HttpPost] 
    [ActionName("ZipFileAction")] 
    public HttpResponseMessage ZipFiles([FromBody]int[] id) 
    { 
     if (id == null) 
     {//Required IDs were not provided 
      throw new HttpResponseException(new HttpResponseMessage(HttpStatusCode.BadRequest)); 
     } 

     List<Document> documents = new List<Document>(); 
     using (var context = new ApplicationDbContext()) 
     { 
      foreach (int NextDocument in id) 
      { 
       Document document = context.Documents.Find(NextDocument); 

       if (document == null) 
       { 
        throw new HttpResponseException(new HttpResponseMessage(HttpStatusCode.NotFound)); 
       } 

       documents.Add(document); 
      } 
      var streamContent = new PushStreamContent((outputStream, httpContext, transportContent) => 
      { 
       try 
       { 
        using (var zipFile = new ZipFile()) 
        { 
         foreach (var d in documents) 
         { 
          var dt = d.DocumentDate.ToString("y").Replace('/', '-').Replace(':', '-'); 
          string fileName = String.Format("{0}-{1}-{2}.pdf", dt, d.PipeName, d.LocationAb); 
          FileInfo fi = new FileInfo(d.DocumentUrl); 
          var fileReadStream = fi.OpenRead(); 
          var fileSize = (int)fi.Length; 
          var fileContent = new byte[fileSize]; 
          fileReadStream.Read(fileContent, 0, fileSize); 
          zipFile.AddEntry(fileName, fileContent); 
         } 
         zipFile.Save(outputStream); //Null Reference Exception 
        } 
       } 

       finally 
       { 
        outputStream.Close(); 
       } 
      }); 
      streamContent.Headers.ContentType = new MediaTypeHeaderValue("application/octet-stream"); 
      streamContent.Headers.ContentDisposition = new ContentDispositionHeaderValue("attachment"); 
      streamContent.Headers.ContentDisposition.FileName = "reports.zip"; 

      var response = new HttpResponseMessage(HttpStatusCode.OK) 
      { 
       Content = streamContent 
      }; 
      return response; 
     } 
    } 
} 

Answer 2

PushStreamContent用於數據流。我認爲你應該創建一個臨時zip文件，並將其傳遞給Response。

例

public FileResult ZipFiles(...) 
{ 
    // create a temporary file 

    return File("path/to/file.zip", System.Net.Mime.MediaTypeNames.Application.Octet); 
}