我無法讓我的菜單中選擇當前項目,這裏是代碼:識別和風格菜單項的當前頁
$sql = "SELECT * FROM kurchi_pages ORDER BY id LIMIT 1,5";
$res = mysql_query($sql);
$site_url = "http://swenflea/swenflea.com/";
if(!isset($_GET['page']) || !isset($_GET['post'])) {
echo '<li id="current"><a href="' . $site_url . '">Home</a></li>';
} else {
echo '<li><a href="' . $site_url . '">Home</a></li>';
}
if (isset($_GET['page']) || isset($_GET['post'])) {
while($row = mysql_fetch_assoc($res)) {
if ($_GET['page'] != "" . $row["url"] . "" || isset($_GET['page']))
{
$itemis = '<li><a href="' . $site_url . '' . $row['url'] . '/">' . $row['nav_name'] . '</a></li>';
} else {
$itemis = '<li id="current"><a href="' . $site_url . '' . $row['url'] . '/">' . $row['nav_name'] . '</a></li>';
}
echo $itemis;
}
} else {
while($row = mysql_fetch_assoc($res)) {
echo '<li><a href="' . $site_url . '' . $row['url'] . '/">' . $row['nav_name'] . '</a></li>';
}
}
爲什麼不這項工作?
你好,我不能得到這個代碼,這個代碼做什麼..? ** if($ _GET ['page']!=「」。$ row [「url」]。「」|| isset($ _ GET ['page']))**是否正常工作..? – Chandresh 2011-05-12 07:05:04