我有以下的數據幀:如何加快組內累計金額?
id<-c(1,1,1,1,1,3,3,3,3)
spent<-c(10,20,30,40,50,60,70,80,90)
date<-c("11-11-07","11-11-07","23-11-07","12-12-08","17-12-08","11-11-07","23-11-07","23- 11-07","16-01-08")
df<-data.frame(id,date,spent)
df$date2<-as.Date(as.character(df$date), format = "%d-%m-%y")
id date spent date2
1 1 11-11-07 10 2007-11-11
2 1 11-11-07 20 2007-11-11
3 1 23-11-07 30 2007-11-23
4 1 12-12-08 40 2008-12-12
5 1 17-12-08 50 2008-12-17
6 3 11-11-07 60 2007-11-11
7 3 23-11-07 70 2007-11-23
8 3 23-11-07 80 2007-11-23
9 3 16-01-08 90 2008-01-16
我需要每個id
每天來計算總和spent
,包括它的框架工作如下:
id date spent date2 sum.spent
1 1 11-11-07 10 2007-11-11 10
2 1 11-11-07 20 2007-11-11 30
3 1 23-11-07 30 2007-11-23 30
4 1 12-12-08 40 2008-12-12 40
5 1 17-12-08 50 2008-12-17 50
6 3 11-11-07 60 2007-11-11 60
7 3 23-11-07 70 2007-11-23 70
8 3 23-11-07 80 2007-11-23 150
9 3 16-01-08 90 2008-01-16 90
下面的腳本運行良好(除了第一行不是什麼大問題):
df$spent2<-NA
for (a in 2:9)
if (df[a,1]==df[a-1,1]&& df[a,4]==df[a-1,4])
(df[a,5]=df[a,3]+df[a-1,3])else(df[a,5]=df[a,3])
但是由於行數在我的實際數據集中大約有150萬,上面的腳本需要5天才能執行。我想知道你是否可以建議一種更有效的方式來編寫這些代碼並達到相同的目標。
它工作正常,也很快......感謝伴侶! – AliCivil