不能獲取包含的文件連接到數據庫

Question

我必須錯過簡單的東西，但我沒有看到它。下面的代碼很好。

<?php 
$res = mysql_connect("localhost", "newuser", ""); 
mysql_select_db("supplydb"); 
function filter($data) 
{ 
    $data = trim(htmlentities(strip_tags($data))); 
    if (get_magic_quotes_gpc()) 
     $data = stripslashes($data); 
    $data = mysql_real_escape_string($data); 
    return $data; 
} 
error_reporting(0); 

require("../codebase/grid_connector.php"); 

$mask5 = filter($_GET["var1"]); 

//Get Category ID 
$cat = mysql_query("SELECT category FROM submissions WHERE submissions.submission_id='$mask5'"); 
$rows = mysql_fetch_array($cat, MYSQL_ASSOC); 
$array = filter($rows['category']); 
//Get Manufactuer ID 
$man = mysql_query("SELECT manufacturer_id FROM submissions WHERE submissions.submission_id='$mask5'"); 
$arows = mysql_fetch_array($man, MYSQL_ASSOC); 
$array1 = filter($arows['manufacturer_id']); 
function formatting($row) 
{ 
    $data = $row->get_value("fda_approved"); 
    if ($data == 1) 
     $row->set_value("fda_approved", Yes); 
    else 
     $row->set_value("fda_approved", No); 
} 
$gridConn = new GridConnector($res, "MySQL"); 

function myUpdate($action) 
{ 
    $data6 = $action->get_id(); 
    $cat_id = mysql_query("SELECT category FROM submissions WHERE submissions.submission_id ='{$data6}'") or die("Error in query: $query. " . mysql_error()); 
    $rows56 = mysql_fetch_array($cat_id, MYSQL_ASSOC); 
     $array = filter($rows56['category']); 
    $status = $action->get_value("approval_status"); 
    $gridConn = new GridConnector($res, "MySQL"); 
    mysql_query("UPDATE submissions SET approval_status='{$status}' WHERE submissions.submission_id='{$data6}'") or die("Error in query: $query. " . mysql_error()); 
    $action->success; 
} 
$gridConn->event->attach("beforeUpdate", "myUpdate"); 
$gridConn->event->attach("beforeRender", "formatting"); 
$gridConn->render_sql("SELECT * FROM submissions JOIN products ON products.product_id = submissions.product_id and submissions.category='$array' and submissions.manufacturer_id='$array1' and submissions.approval_status='0'", "submission_id", "item_number,description,list_price,sugg_price,quantity_per_unit,fda_approved,gpo_contract_number, approval_status"); 
?> 

此代碼不

<?php 
require("../site_globals/dbc_simple.php"); 
//$res = mysql_connect("localhost", "newuser", ""); 
//mysql_select_db("supplydb"); 
error_reporting(0); 
require("../codebase/grid_connector.php"); 
$mask5 = filter($_GET["var1"]); 
//Get Category ID 
$cat = mysql_query("SELECT category FROM submissions WHERE submissions.submission_id='$mask5'"); 
$rows = mysql_fetch_array($cat, MYSQL_ASSOC); 
$array = filter($rows['category']); 
//Get Manufactuer ID 
$man = mysql_query("SELECT manufacturer_id FROM submissions WHERE submissions.submission_id='$mask5'"); 
$arows = mysql_fetch_array($man, MYSQL_ASSOC); 
$array1 = filter($arows['manufacturer_id']); 
function formatting($row) 
{ 
    $data = $row->get_value("fda_approved"); 
    if ($data == 1) 
     $row->set_value("fda_approved", Yes); 
    else 
     $row->set_value("fda_approved", No); 
} 
$gridConn = new GridConnector($res, "MySQL"); 

function myUpdate($action) 
{ 
    $data6 = $action->get_id(); 
    $cat_id = mysql_query("SELECT category FROM submissions WHERE submissions.submission_id ='{$data6}'") or die("Error in query: $query. " . mysql_error()); 
    $rows56 = mysql_fetch_array($cat_id, MYSQL_ASSOC); 
     $array = filter($rows56['category']); 
    $status = $action->get_value("approval_status"); 
    $gridConn = new GridConnector($res, "MySQL"); 
    mysql_query("UPDATE submissions SET approval_status='{$status}' WHERE submissions.submission_id='{$data6}'") or die("Error in query: $query. " . mysql_error()); 
    $action->success; 
} 
$gridConn->event->attach("beforeUpdate", "myUpdate"); 
$gridConn->event->attach("beforeRender", "formatting"); 
$gridConn->render_sql("SELECT * FROM submissions JOIN products ON products.product_id = submissions.product_id and submissions.category='$array' and submissions.manufacturer_id='$array1' and submissions.approval_status='0'", "submission_id", "item_number,description,list_price,sugg_price,quantity_per_unit,fda_approved,gpo_contract_number, approval_status"); 
?> 

唯一的區別是在頂部的包括文件和所有包含文件是：

<?php 
$res = mysql_connect("localhost", "newuser", ""); 
mysql_select_db("supplydb"); 
?> 

林相當新的PHP，但這看起來很簡單，我不確定在翻譯中迷路了什麼。順便說一下，這在其他頁面上工作正常，所以它必須與$ gridConn = new GridConnector（$ res，「MySQL」）有關;但我不知道足夠了解什麼。我正在使用DHTMLX JavaScript庫。它可能與此有關嗎？我在這裏嘗試了一切。想法？

Answer 1

Im getting: XML Parsing Error: XML or text declaration not at start of entity Location

問題是不是在數據庫連接本身，它正常工作，並生成數據，但結果XML損壞，因爲一些輸出被前連接器的代碼開始。

檢查../site_globals/dbc_simple.php - 在關閉「？>」標記後可能有一些空格|換行符 - 刪除它們，它將解決問題。

這樣的空格|換行符不會對HTML頁面造成傷害，但對於XML數據，文檔開始處的任何額外字符都可能導致問題。