按鈕看起來不激活

Question

我想要一個按鈕從一開始就看起來被激活（透明）。 我的選擇：

<selector xmlns:android="http://schemas.android.com/apk/res/android"> 
<item android:state_activated="true" > 
    <shape> 
     <solid 
      android:color="@android:color/transparent" /> 
    </shape> 
</item> 
<item android:state_pressed="false" android:state_focused="false" android:state_activated="false"> 
    <shape> 
     <gradient 
      android:startColor="#ef4444" 
      android:endColor="#992f2f" 
      android:angle="270" /> 
    </shape> 
</item> 

而且按鈕的代碼：

<Button 
    android:background="@drawable/my_bg" 
    android:state_activated="true" 
/> 

按鈕的默認顏色是紅色的，所以我想這個問題是在安卓state_activated =「真」。我該如何解決這個問題？

Answer 1

請使用它會幫助你

<?xml version="1.0" encoding="utf-8"?> 
<selector xmlns:android="http://schemas.android.com/apk/res/android"> 

    <item android:state_focused="true"><shape xmlns:android="http://schemas.android.com/apk/res/android" android:shape="rectangle"> 
      <solid android:color="#2d7ebb" /> 

      <corners android:radius="5dp"> 
       <stroke android:width="2dip" android:color="#2d7ebb" /> 
      </corners> 
     </shape></item> 
    <item android:state_pressed="true"><shape xmlns:android="http://schemas.android.com/apk/res/android" android:shape="rectangle"> 
      <solid android:color="#2d7ebb" /> 

      <corners android:radius="5dp"> 
       <stroke android:width="2dip" android:color="#2d7ebb" /> 
      </corners> 
     </shape></item> 
    <item><shape xmlns:android="http://schemas.android.com/apk/res/android" android:shape="rectangle"> 
      <solid android:color="#55acee" /> 

      <stroke android:width="2dip" android:color="#55acee" /> 

      <corners android:radius="5dp" /> 
     </shape></item> 

</selector>