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如何使用jaxb獲取嵌套xml的對象。我有以下XML -使用jaxb的XML解析器
<?xml version="1.0" ?>
<file>
<markups>
<markup>
<author>author</author>
<name>3w2fg</name>
<source>Mobile_iPad</source>
<createdOn>2013-05-20T11:22:23</createdOn>
<entities>
<entity>
<entityWdth>209</entityWdth>
<entityColor>
<red>127.5</red>
<green>0</green>
<blue>127.5</blue>
</entityColor>
<entityFillColor>
<red>227.5</red>
<green>0</green>
<blue>327.5</blue>
</entityFillColor>
<entityRadian>0</entityRadian>
<entityEndY>304</entityEndY>
<entityStX>438</entityStX>
<entityTypeCode>7</entityTypeCode>
<entityPageNo>1</entityPageNo>
<entityHt>183</entityHt>
<entityCenterX>542.5</entityCenterX>
<entityName>Rectangle</entityName>
<entityStY>121</entityStY>
<entityEndX>647</entityEndX>
<entityCenterY>212.5</entityCenterY>
</entity>
</entities>
</markup>
</markups>
<name>7987ab12-4915-49e5-8bbd-f98d6054ef6b.JPG</name>
<fileName>IMG_0008.JPG</fileName>
</file>
我使用JAXB解組此爲下 -
JAXBContext jbContext = JAXBContext.newInstance(com.arc.markupinfo.generated.File.class);
com.arc.markupinfo.generated.ObjectFactory factory = new com.arc.markupinfo.generated.ObjectFactory();
com.arc.markupinfo.generated.File fileObj = factory.createFile();
Unmarshaller unmarshaller = jbContext.createUnmarshaller();
fileObj = (com.arc.markupinfo.generated.File) unmarshaller.unmarshal(new File(xmlLocation));
fileObj.getFileName();
的對象與除entityColor.Red所有值創建...並entityFillColor.Red ....這些值來作爲0,0,0而XML說明它有正確的價值觀
什麼相應的對象模型是什麼樣子? –