1
我想要的只是一個簡單的記住我。我讀http://static.springsource.org/spring-security/site/docs/3.0.x/reference/remember-me.html簡單的春天<記住我/> ...請幫助
我迄今所做的：
- 創建了自己的
UserDetailsService與休眠/ JPA工作。 我的impl。不考慮任何記得，我的東西 - 考慮配置通過appContext
<security:remember-me key="89dqj219dn910lsAc12" user-service-ref="jpaUserDetailsService" token-validity-seconds="864000"/> - 經過，該Cookie
SPRING_SECURITY_REMEMBER_ME_COOKIE是真正建立 - 登錄到安全的網站，當我重新啓動我的瀏覽器，它的工作原理
，我不斷收到一個錯誤：
org.springframework.security.access.AccessDeniedException：訪問被拒絕 認證對象的字符串：org.springframework.security.authentication.Rem emberMeAuthenticationToken @ 9ab72a70：負責人：[email protected]：用戶名：myad;密碼保護];啓用：true; AccountNonExpired：true; credentialsNonExpired：true; AccountNonLocked：true;個人信息：65537; ;證書：[PROTECTED];已驗證：true;詳細信息：org.sprin[email protected]957e：RemoteIpAddress：127.0.0.1; SessionId：null;授予的權限：ROLE_ADMIN，ROLE_USER
這裏是我的secContext.xml：
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:security="http://www.springframework.org/schema/security"
xsi:schemaLocation="
http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/security
http://www.springframework.org/schema/security/spring-security-3.0.xsd">
<security:global-method-security pre-post-annotations="enabled">
</security:global-method-security>
<security:http use-expressions="true" access-denied-page="/accessDenied">
<security:form-login
login-page="/login"
login-processing-url="/loginProcess"
default-target-url="/intro"
authentication-failure-url="/login?login_error=1"
/>
<security:logout
logout-url="/logout"
logout-success-url="/logoutSuccess"/>
<security:intercept-url pattern="/**" access="permitAll"/>
<security:intercept-url pattern="/login" access="permitAll"/>
<security:intercept-url pattern="/styles/**" access="permitAll"/>
<security:intercept-url pattern="/scripts/**" access="permitAll"/>
<security:remember-me key="89dqj219dn910lsAc12" user-service-ref="jpaUserDetailsService"
token-validity-seconds="864000"/>
</security:http>
<security:authentication-manager alias="authenticationManager">
<security:authentication-provider user-service-ref="jpaUserDetailsService">
<security:password-encoder hash="sha">
</security:password-encoder>
</security:authentication-provider>
</security:authentication-manager>
<bean id="rememberMeFilter" class=
"org.springframework.security.web.authentication.rememberme.RememberMeAuthenticationFilter">
<property name="rememberMeServices" ref="rememberMeServices"/>
<property name="authenticationManager" ref="authenticationManager"/>
</bean>
<bean id="rememberMeServices" class=
"org.springframework.security.web.authentication.rememberme.TokenBasedRememberMeServices">
<property name="userDetailsService" ref="jpaUserDetailsService"/>
<property name="key" value="89dqj219dn910lsAc12"/>
</bean>
<bean id="rememberMeAuthenticationProvider" class=
"org.springframework.security.authentication.RememberMeAuthenticationProvider">
<property name="key" value="89dqj219dn910lsAc12"/>
</bean>
</beans>
最後一些調試跟蹤
03:45:14.598 [[email protected]] DEBUG o.s.w.b.a.s.HandlerMethodInvoker - Invoking request handler method: public java.lang.String de.myapp.controller.bstController.showbstpage(java.lang.String,javax.servlet.http.HttpServletResponse)
03:45:14.598 [[email protected]] DEBUG o.s.s.a.i.a.MethodSecurityInterceptor - Secure object: ReflectiveMethodInvocation: public java.lang.String de.myapp.controller.bstController.showbstpage(java.lang.String,javax.servlet.http.HttpServletResponse); target is of class [de.myapp.controller.bstController]; Attributes: [[authorize: 'isFullyAuthenticated() and #username == principal.username', filter: 'null', filterTarget: 'null']]
03:45:14.598 [[email protected]] DEBUG o.s.s.a.i.a.MethodSecurityInterceptor - Previously Authenticated: org.spring[email protected]9ab72a70: Principal: [email protected]: Username: myad; Password: [PROTECTED]; Enabled: true; AccountNonExpired: true; credentialsNonExpired: true; AccountNonLocked: true; PersonalInformation: 65537; ; Credentials: [PROTECTED]; Authenticated: true; Details: org.sprin[email protected]957e: RemoteIpAddress: 127.0.0.1; SessionId: null; Granted Authorities: ROLE_ADMIN, ROLE_USER
03:45:14.599 [[email protected]] DEBUG o.s.c.c.s.GenericConversionService - Converting value false of [TypeDescriptor java.lang.Boolean] to [TypeDescriptor java.lang.Boolean]
03:45:14.599 [[email protected]] TRACE o.s.c.c.s.GenericConversionService - Matched cached converter NO_OP
03:45:14.599 [[email protected]tp-10131947-7] DEBUG o.s.c.c.s.GenericConversionService - Converted to false
03:45:14.599 [[email protected]] DEBUG o.s.s.access.vote.AffirmativeBased - Voter: org.springframewor[email protected]a866a9, returned: -1
03:45:14.599 [[email protected]] DEBUG o.s.s.access.vote.AffirmativeBased - Voter: [email protected], returned: 0
03:45:14.599 [[email protected]] DEBUG o.s.s.access.vote.AffirmativeBased - Voter: [email protected]d6f, returned: 0
我真的不知道從哪裏繼續調試。我錯過了什麼？我是否必須創建自己的記住我的實現？
我真的欣賞演示泉記得，我的默認實現工作示例應用程序...
-------- ----------編輯 -
我剛編譯並運行springsecurity本身的記憶我參考應用程序：spring-security\samples\tutorial帳戶應用程序和聯繫人應用程序。其實我有完全一樣的問題？！？。我已經嘗試過Firefox，Opera和ie ...我破碎了...