如何在同一個表中執行選定查詢的mysql更新？

Question

UPDATE suggest 
SET 
` post_id`="5286" 
where 
    `post_id` IN 

(SELECT `post_id` FROM `suggest` WHERE `word` LIKE "%word%") 

Answer 1

這裏沒有必要使用子查詢。

UPDATE suggest 
SET `post_id`="5286" 
WHERE `word` LIKE "%word%" 

Answer 2

MySQL Error 1093 - Can't specify target table for update in FROM clause

下面是關於這方面的文章。

您可以使用此查詢來實現此目的。

update suggest as a inner join (select post_id from suggest where word like '%word%') as b on a.post_id = b.post_id set a.post_id="5286";