JavaFX ActionEvent矩形

Question

總之：

我正在創建AI和GUI的紙牌遊戲。用戶的手顯示在遊戲播放界面上，我還沒有完成界面，但我打算在屏幕上添加一張卡片圖像到矩形。我找到了一個類似的帖子，而不是採用5種幾乎相同的方法，而是試圖實現相同的想法。但是，我遇到了意想不到的事情。下面是從我的控制器類相關的代碼：

/** This is where the players hand will be displayed. */ 
@FXML 
private Rectangle card1, card2, card3, card4, card5; 

public void playThisCard(final ActionEvent event) { 
    if (event.getSource() == card1) { 
     System.out.println("played card 1"); 
    } else if (event.getSource() == card2) { 
     System.out.println("played card 2"); 
    } else if (event.getSource() == card3) { 
     System.out.println("played card 3"); 
    } else if (event.getSource() == card4) { 
     System.out.println("played card 4"); 
    } else if (event.getSource() == card5) { 
     System.out.println("played card 5"); 
    } else { 
     System.out.println("no card played"); 
    } 
} 

的UI始建於場景生成器，因此在矩形的FXML標籤，控制器正確綁定，並且我已經成功地得到了其他方法來對用戶執行輸入到控件。

Exception in thread "JavaFX Application Thread" java.lang.IllegalArgumentException: argument type mismatch 
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) 
at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:62) 
at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43) 
at java.lang.reflect.Method.invoke(Method.java:497) 
at sun.reflect.misc.Trampoline.invoke(MethodUtil.java:71) 
at sun.reflect.GeneratedMethodAccessor1.invoke(Unknown Source) 
at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43) 
at java.lang.reflect.Method.invoke(Method.java:497) 
at sun.reflect.misc.MethodUtil.invoke(MethodUtil.java:275) 
at javafx.fxml.FXMLLoader$MethodHandler.invoke(FXMLLoader.java:1769) 
at javafx.fxml.FXMLLoader$ControllerMethodEventHandler.handle(FXMLLoader.java:1657) 
at com.sun.javafx.event.CompositeEventHandler.dispatchBubblingEvent(CompositeEventHandler.java:86) 
at com.sun.javafx.event.EventHandlerManager.dispatchBubblingEvent(EventHandlerManager.java:238) 
at com.sun.javafx.event.EventHandlerManager.dispatchBubblingEvent(EventHandlerManager.java:191) 
at com.sun.javafx.event.CompositeEventDispatcher.dispatchBubblingEvent(CompositeEventDispatcher.java:59) 
at com.sun.javafx.event.BasicEventDispatcher.dispatchEvent(BasicEventDispatcher.java:58) 
at com.sun.javafx.event.EventDispatchChainImpl.dispatchEvent(EventDispatchChainImpl.java:114) 
at com.sun.javafx.event.BasicEventDispatcher.dispatchEvent(BasicEventDispatcher.java:56) 
at com.sun.javafx.event.EventDispatchChainImpl.dispatchEvent(EventDispatchChainImpl.java:114) 
at com.sun.javafx.event.BasicEventDispatcher.dispatchEvent(BasicEventDispatcher.java:56) 
at com.sun.javafx.event.EventDispatchChainImpl.dispatchEvent(EventDispatchChainImpl.java:114) 
at com.sun.javafx.event.EventUtil.fireEventImpl(EventUtil.java:74) 
at com.sun.javafx.event.EventUtil.fireEvent(EventUtil.java:54) 
at javafx.event.Event.fireEvent(Event.java:198) 
at javafx.scene.Scene$ClickGenerator.postProcess(Scene.java:3470) 
at javafx.scene.Scene$ClickGenerator.access$8100(Scene.java:3398) 
at javafx.scene.Scene$MouseHandler.process(Scene.java:3766) 
at javafx.scene.Scene$MouseHandler.access$1500(Scene.java:3485) 
at javafx.scene.Scene.impl_processMouseEvent(Scene.java:1762) 
at javafx.scene.Scene$ScenePeerListener.mouseEvent(Scene.java:2494) 
at com.sun.javafx.tk.quantum.GlassViewEventHandler$MouseEventNotification.run(GlassViewEventHandler.java:352) 
at com.sun.javafx.tk.quantum.GlassViewEventHandler$MouseEventNotification.run(GlassViewEventHandler.java:275) 
at java.security.AccessController.doPrivileged(Native Method) 
at com.sun.javafx.tk.quantum.GlassViewEventHandler.lambda$handleMouseEvent$355(GlassViewEventHandler.java:388) 
at com.sun.javafx.tk.quantum.QuantumToolkit.runWithoutRenderLock(QuantumToolkit.java:389) 
at com.sun.javafx.tk.quantum.GlassViewEventHandler.handleMouseEvent(GlassViewEventHandler.java:387) 
at com.sun.glass.ui.View.handleMouseEvent(View.java:555) 
at com.sun.glass.ui.View.notifyMouse(View.java:937) 

Answer 1

如果你想處理上Rectangle的鼠標點擊，您可以使用onMouseClickedProperty。

所以我想在你的FXML文件，你有這樣的事情：

onMouseClicked="#playThisCard" 

但如果你在提到財產的簽名看看：

public final ObjectProperty<EventHandler<? super MouseEvent>> onMouseClickedProperty 

你會看到它會未能通過ActionEvent但MouseEvent，因此

public void playThisCard(final MouseEvent event) 

是第e正確的簽名來處理從鼠標點擊中獲得的事件。