在Ansible

從另一個字典收集字典我有一些字典：在Ansible

users_to_add: 
    - username: Harley Quinn 
     login: 90987264 
     group: mininform 
     group_desc: "Some random data for description" 
     personal_data: 
     - first_name: Harley 
      last_name: Quinn 
      mail: [email protected] 
      telnum: +7777777777 
      jobtitle: minister 
    - username: Vasya Pupkin 
     login: 77777777 
     group: mininform 
     group_desc: "Some random data for description" 
     personal_data: 
     - first_name: Vasya 
      last_name: Pupkin 
      mail: [email protected] 
      telnum: +7970000000 
      jobtitle: minister

而且我有隻列出工作ansible模塊：

- name: Create needed groups 
    ipa_group: 
     state: present 
     name: "{{ item.group }}" 
     description: "{{ item.group_desc }}" 
     ipa_host: "{{ global_host }}" 
     ipa_user: "{{ global_user }}" 
     ipa_pass: "{{ global_pass }}" 
     validate_certs: no 
     user: [] 
    with_items: 
     - "{{ users_to_add }}"

該模塊要在「用戶」的用戶列表參數，創建一個組並添加用戶。我想像這樣映射字典「users_to_add」：（使用users_to_add字典） {group_name: ["user1", "user2"...]}並將此新字典添加到模塊中。我如何用ansible來完成這項工作？我知道，首先我應該使用

set_fact: 
    new_dict: 
with_items: {{ users_to_add }}

...

再喂這個新字典的模塊，其中關鍵的是組名創造和價值 - 要添加到組的用戶列表中，但我不明白如何與ansible做到這一點...

來源

2016-11-10 Mizeraj

很難理解你想在這裏...'ipa_g達到什麼roup'模塊創建組併爲其分配用戶。但是你遍歷'users_to_add'而不是組。請編輯你的問題，確切地說你想創建哪些組名包含哪些用戶名。 –

我想迭代users_to_add字典，並在新字典中收集所有組名和用戶登錄，其中：{group：[擁有此組的所有用戶]，group：...} – Mizeraj

試試這個：

- name: Create needed groups 
    ipa_group: 
     state: present 
     name: "{{ item }}" 
     description: "{{ users_to_add | selectattr('group','equalto',item) | map(attribute='group_desc') | list | first }}" 
     ipa_host: "{{ global_host }}" 
     ipa_user: "{{ global_user }}" 
     ipa_pass: "{{ global_pass }}" 
     validate_certs: no 
     user: "{{ users_to_add | selectattr('group','equalto',item) | map(attribute='username') | list }}" 
    with_items: "{{ users_to_add | map(attribute='group') | list | unique }}"

來源

2016-11-11 06:47:38

非常感謝 - 它按預期工作） – Mizeraj

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