2015-06-16 207 views
0

我想選擇2個屬性,這些屬性在多項選擇測驗中是可變的。我在input中回答了每個問題的正確答案,該答案不會顯示在頁面上。我認爲我選擇2種不同屬性的路線是問題所在。
JQUERY:Jquery多屬性選擇器不工作

 var zz = 1; 

     while (zz <= <?php echo $num_rows ?>){ //I'm 100% postive $num_rows returns a value of 3 
     var zstring = '#answer' + zz; 

     var theanswer = $(zstring).attr('value'); //should return "a" or "c" or whatever the answer is 

     if $("input[name=zz][value=theanswer]").is(':checked') { //this is the line that's not working 

       alert("the code worked"); 
     }  

     zz++;  
     } 

HTML從PHP

echo "<input type='radio' name=" . $question_number ." value='a'> A. " . $chA . "<br><br>"; 
echo "<input type='radio' name=" . $question_number ." value='b'> B. " . $chB . "<br><br>"; 
echo "<input type='radio' name=" . $question_number ." value='c'> C. " . $chC . "<br><br>"; 
echo "<input type='radio' name=" . $question_number ." value='d'> D. " . $chD . "<br><br>"; 
echo "<input type='radio' name=" . $question_number ." value='e'> E. " . $chE . "<br>"; 
echo "<input type='text' id='answer".$question_number."' style='display: none;' value='".$correct."' />"; 

回答

2

我看到,在if語句,你有呼應這樣的:

if $("input[name=zz][value=theanswer]").is(':checked') { //this is the line 

它應該是:

if ($('input[name="zz"][value="theanswer"]').is(':checked')) { //this is the line 
+0

我誤會了問題,這裏是你的答案小提琴https://jsfiddle.net/h5s7bn1v/4/ –