在數據庫中插入多個值使用php

Question

我想在我的數據庫中插入多個值。但是我找不到解決方案來做我想做的事。

我在這裏的問題是，我有值的像 ("6.40","6.50","7.00","7.10","7.20","7.30") 一個陣列，我想每行中插入這些值，像6.40將一行存儲相應的ID「1」。

類似地， 「6.50」，將在 「2」 的ID存儲。該ID將只是自動遞增。

類似地，它將插入數據庫中的值，直到數組爲空。如果任何人有任何想法如何解決這個問題，請幫助我！請承擔我的疑慮。我是PHP新手。提前致謝。

for ($i=0;$i < count($slot_timings1); $i++) 
{ 
    $q = $this->link->prepare('INSERT INTO doctor_appointment (doctor_name,doctor_id,appointment_date,slot_name,slot_timings) VALUES (:doctor_name,:doctor_id,:appointment_date,:slot_name,slot_timings)'); 
    $q->execute(array(':doctor_name'=>$doctor_name,':doctor_id'=>$doctor_id, ':appointment_date'=>$appointment_date,':slot_name'=>$slot_name,':slot_timings'=‌​>$slot_timings)); 
} 
$counts = $q->rowCount(); 
return $counts; 

Answer 1

試試這個：

for ($i=0;$i < count($slot_timings1); $i++) 
{ 
$q = $this->link->prepare('INSERT INTO doctor_appointment (doctor_name,doctor_id,appointment_date,slot_name,slot_timings) VALUES (:doctor_name,:doctor_id,:appointment_date,:slot_name,slot_timings)'); 
$q->execute(array(':doctor_name'=>$doctor_name,':doctor_id'=>$doctor_id, ':appointment_date'=>$appointment_date,':slot_name'=>$slot_name,':slot_timings'=‌​>$slot_timings1[$i])); 
} 
$counts = $q->rowCount(); 
return $counts; 

Answer 2

嘗試這樣的事情。

foreach($slot_timings1 as $data) 
    { 
     $q = $this->link->prepare('INSERT INTO doctor_appointment (doctor_name,doctor_id,appointment_date,slot_name,slot_timings) VALUES (:doctor_name,:doctor_id,:appointment_date,:slot_name,slot_timings)'); 
     $q->execute(array(':doctor_name'=>$doctor_name,':doctor_id'=>$doctor_id, ':appointment_date'=>$appointment_date,':slot_name'=>$slot_name,':slot_timings'=‌​>$data)); 
    } 

Answer 3

試試這個：

if(is_array($slot_timings1) && !empty($slot_timings1)) 
{ 
foreach ($slot_timings1 as $slot_timing) 
{ 
$q = $this->link->prepare('INSERT INTO doctor_appointment (doctor_name,doctor_id,appointment_date,slot_name,slot_timings) VALUES (:doctor_name,:doctor_id,:appointment_date,:slot_name,:slot_timings)'); 

$q->execute(array(':doctor_name'=>$doctor_name,':doctor_id'=>$doctor_id, ':appointment_date'=>$appointment_date,':slot_name'=>$slot_name,':slot_timings'=>$slot_timing)); 
} 

return count($slot_timings1);  
} 

Answer 4

if(is_array($slot_timings1)){ 


sort($slot_timings1); //Sort the elements of the array in ascending 

$sql = "INSERT INTO doctor_appointment (doctor_name,doctor_id,appointment_date,slot_name,slot_timings) VALUES "; 

$query_val = array(); 
foreach($slot_timings1 as $gettime){ 

    $row1 = $doctor_name; 
    $row2 = $doctor_id; 
    $row3 = $appointment_date; 
    $row4 = $slot_name; 
    $row5 = $gettime; 
    $query_val[] = "('$row1', '$row2', '$row3', '$row4', '$row5')"; 
} 

$sql .= implode(',', $query_val); 

mysql_query($sql) or exit(mysql_error()); 
}