限制要顯示的圖像數php

Question

此代碼會導致圖像以頁面內的「隨機」顯示。

<?php 
$myImagesList = array (
    'image1.png', 
    'image2.png', 
    'image3.png', 
    'image4.png' 
); 



shuffle ($myImagesList); 
foreach ($myImagesList as $displayImagesAtRandomOrder) { 
echo '<img src="/imagens/' . $displayImagesAtRandomOrder . '" width="200" height="40" border="0" />'; 
} 
?> 

例如：

image1.png image3.png image2.png image4.png

F5 reshesh頁

image2.png image3.png image4.png image3.png

F5 reshesh page

image1.png image4.png image3.png image2.png

F5 reshesh頁

image2.png image3.png image1.png image4.png

但我怎麼每次只顯示兩個圖像？ 例如：

image1.png image3.png

F5 reshesh頁

image3.png image2.png

F5 reshesh頁

image2.png image4.png

F5 reshesh page

image3.png image1.png

Answer 1

一個簡單的方法是隻限制迭代

<?php 
$myImagesList = array (
    'image1.png', 
    'image2.png', 
    'image3.png', 
    'image4.png' 
); 

$count = 1; //set up our count, start at our first image 
$imagesToShow = 2; //how many images we want to show 



shuffle ($myImagesList); 
foreach ($myImagesList as $displayImagesAtRandomOrder) { 
    //if we have reached our count, let's break out of our loop 
    if($count > $imagesToShow) { break; } 
    echo '<img src="/imagens/' . $displayImagesAtRandomOrder . '" width="200" height="40" border="0" />'; 
    $count++; //increase our count each loop iteration 
} 
?> 

Answer 2

洗牌之後他們，你可以循環兩次服用前兩個（0和1）項數組中：

shuffle ($myImagesList); 
for ($i=0; $i<2; $i++) { 
echo '<img src="/imagens/' . $myImagesList[$i] . '" width="200" height="40" border="0" />'; 
} 

Answer 3

使用的for-loop代替foreach只有2 iteraction：

<?php 

$myImagesList = array (
    'image1.png', 
    'image2.png', 
    'image3.png', 
    'image4.png' 
); 

shuffle ($myImagesList); 

for($index = 0; $index < 2; $index++){ 
    echo '<img src="/imagens/' . $myImagesList[$index] . '" width="200" height="40" border="0" />'; 
} 

?> 

如果你不知道beetwen的兩個關鍵字的區別是：what are the difference between for loop & for each loop in php

Answer 4

$imageCounter = 0; 
foreach ($myImagesList as $displayImagesAtRandomOrder) { 
    $imageCounter++; 
    echo '<img src="/imagens/' . $displayImagesAtRandomOrder . '" width="200" height="40" border="0" />'; 
    if (!($imageCounter % 2)) break; 
} 

上面的代碼將只顯示2個圖像。您可以將該號碼更改爲您想要的任何號碼。希望能幫助到你。