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我在將this C# code轉換爲WebAPI 2 VB.Net項目時遇到了一些困難。將PushStreamContent C#代碼轉換爲VB.Net時出錯WebAPI 2
這裏是原來的C#代碼
[HttpGet]
public HttpResponseMessage FromImages() {
var imageStream = new ImageStream();
Func<Stream, HttpContent, TransportContext, Task> func = imageStream.WriteToStream;
var response = Request.CreateResponse();
response.Content = new PushStreamContent(func);
response.Content.Headers.Remove("Content-Type");
response.Content.Headers.TryAddWithoutValidation("Content-Type", "multipart/x-mixed-replace;boundary=" + imageStream.Boundary);
return response;
}
internal class ImageStream {
public object Boundary { get; private set; } = "HintDesk";
public async Task WriteToStream(Stream outputStream, HttpContent content, TransportContext context) {
byte[] newLine = Encoding.UTF8.GetBytes("\r\n");
foreach (var file in Directory.GetFiles(@"TestData\Images", "*.jpg")) {
var fileInfo = new FileInfo(file);
var header = $"--{Boundary}\r\nContent-Type: image/jpeg\r\nContent-Length: {fileInfo.Length}\r\n\r\n";
var headerData = Encoding.UTF8.GetBytes(header);
await outputStream.WriteAsync(headerData, 0, headerData.Length);
await fileInfo.OpenRead().CopyToAsync(outputStream);
await outputStream.WriteAsync(newLine, 0, newLine.Length);
await Task.Delay(1000/30);
}
}
}
下面是VB.Net翻譯
<HttpGet> _
Public Function FromImages() As HttpResponseMessage
Dim imageStream = New ImageStream()
Dim func As Func(Of Stream, HttpContent, TransportContext, Task) = imageStream.WriteToStream
Dim response = Request.CreateResponse()
response.Content = New PushStreamContent(func)
response.Content.Headers.Remove("Content-Type")
response.Content.Headers.TryAddWithoutValidation("Content-Type", "multipart/x-mixed-replace;boundary=" + imageStream.Boundary)
Return response
End Function
Friend Class ImageStream
Public Function WriteToStream(outputStream As Stream, content As HttpContent, context As TransportContext) As Task
Dim newLine As Byte() = Encoding.UTF8.GetBytes(vbCr & vbLf)
For Each file As var In Directory.GetFiles("TestData\Images", "*.jpg")
Dim fileInfo = New FileInfo(file)
Dim header = "--{Boundary}" & vbCr & vbLf & "Content-Type: image/jpeg" & vbCr & vbLf & "Content-Length: {fileInfo.Length}" & vbCr & vbLf & vbCr & vbLf
Dim headerData = Encoding.UTF8.GetBytes(header)
Await outputStream.WriteAsync(headerData, 0, headerData.Length)
Await fileInfo.OpenRead().CopyToAsync(outputStream)
Await outputStream.WriteAsync(newLine, 0, newLine.Length)
Await Task.Delay(1000/30)
Next
End Function
End Class
我看到兩個問題:
在這條線是一個「參數沒有爲'Public Function WriteToStream ...'的參數'context'指定'
昏暗FUNC作爲Func鍵(中流,HttpContent,TransportContext,任務)= imageStream.WriteToStream
的重載決策失敗,因爲沒有可訪問的 '新' 可以用這些參數
響應被稱爲。內容=新PushStreamContent(FUNC)
我想,我沒有正確翻譯這一點,但我很難找到在VB.Net任何實例爲了我想要完成的事情。有人能告訴我我做錯了什麼嗎?
的伎倆,和漂亮的風風火火的邊界屬性 – user1532208