如何解決與HttpUrlConnection和所有新的API的代碼23

Question

我想從服務器進行登錄檢查我已經從互聯網上找到這個代碼，但現在HttpClient和其他一些已被棄用的API 23和更高。但我無法使用HttpUrlConnection，libray和所有更新進行修改。

主要活動：

package com.example.login; 

import java.util.ArrayList; 

import org.apache.http.NameValuePair; 
import org.apache.http.message.BasicNameValuePair; 

import android.app.Activity; 
import android.os.Bundle; 
import android.view.View; 
import android.widget.Button; 
import android.widget.EditText; 
import android.widget.TextView; 

public class LoginLayout extends Activity { 
    EditText un,pw; 
    TextView error; 
    Button ok; 
    /** Called when the activity is first created. */ 
    @Override 
    public void onCreate(Bundle savedInstanceState) { 
     super.onCreate(savedInstanceState); 
     setContentView(R.layout.main); 
     un=(EditText)findViewById(R.id.et_un); 
     pw=(EditText)findViewById(R.id.et_pw); 
     ok=(Button)findViewById(R.id.btn_login); 
     error=(TextView)findViewById(R.id.tv_error); 

     ok.setOnClickListener(new View.OnClickListener() { 

      @Override 
      public void onClick(View v) { 
       // TODO Auto-generated method stub 

       ArrayList<NameValuePair> postParameters = new ArrayList<NameValuePair>(); 
       postParameters.add(new BasicNameValuePair("username", un.getText().toString())); 
       postParameters.add(new BasicNameValuePair("password", pw.getText().toString())); 

       String response = null; 
       try { 
        response = CustomHttpClient.executeHttpPost("<target page url>", postParameters); 
        String res=response.toString(); 
        res= res.replaceAll("\\s+",""); 
        if(res.equals("1")) 
         error.setText("Correct Username or Password"); 
        else 
         error.setText("Sorry!! Incorrect Username or Password"); 
       } catch (Exception e) { 
        un.setText(e.toString()); 
       } 

      } 
     }); 
    } 
} 

一個CustomClient類：

import java.io.BufferedReader; 
import java.io.IOException; 
import java.io.InputStreamReader; 
import java.net.URI; 
import java.util.ArrayList; 

import org.apache.http.HttpResponse; 
import org.apache.http.NameValuePair; 
import org.apache.http.client.HttpClient; 
import org.apache.http.client.entity.UrlEncodedFormEntity; 
import org.apache.http.client.methods.HttpGet; 
import org.apache.http.client.methods.HttpPost; 
import org.apache.http.conn.params.ConnManagerParams; 
import org.apache.http.impl.client.DefaultHttpClient; 
import org.apache.http.params.HttpConnectionParams; 
import org.apache.http.params.HttpParams; 

public class CustomHttpClient { 
    /** The time it takes for our client to timeout */ 
    public static final int HTTP_TIMEOUT = 30 * 1000; // milliseconds 

    /** Single instance of our HttpClient */ 
    private static HttpClient mHttpClient; 

    /** 
    * Get our single instance of our HttpClient object. 
    * 
    * @return an HttpClient object with connection parameters set 
    */ 
    private static HttpClient getHttpClient() { 
     if (mHttpClient == null) { 
      mHttpClient = new DefaultHttpClient(); 
      final HttpParams params = mHttpClient.getParams(); 
      HttpConnectionParams.setConnectionTimeout(params, HTTP_TIMEOUT); 
      HttpConnectionParams.setSoTimeout(params, HTTP_TIMEOUT); 
      ConnManagerParams.setTimeout(params, HTTP_TIMEOUT); 
     } 
     return mHttpClient; 
    } 

    /** 
    * Performs an HTTP Post request to the specified url with the 
    * specified parameters. 
    * 
    * @param url The web address to post the request to 
    * @param postParameters The parameters to send via the request 
    * @return The result of the request 
    * @throws Exception 
    */ 
    public static String executeHttpPost(String url, ArrayList<NameValuePair> postParameters) throws Exception { 
     BufferedReader in = null; 
     try { 
      HttpClient client = getHttpClient(); 
      HttpPost request = new HttpPost(url); 
      UrlEncodedFormEntity formEntity = new UrlEncodedFormEntity(postParameters); 
      request.setEntity(formEntity); 
      HttpResponse response = client.execute(request); 
      in = new BufferedReader(new InputStreamReader(response.getEntity().getContent())); 

      StringBuffer sb = new StringBuffer(""); 
      String line = ""; 
      String NL = System.getProperty("line.separator"); 
      while ((line = in.readLine()) != null) { 
       sb.append(line + NL); 
      } 
      in.close(); 

      String result = sb.toString(); 
      return result; 
     } finally { 
      if (in != null) { 
       try { 
        in.close(); 
       } catch (IOException e) { 
        e.printStackTrace(); 
       } 
      } 
     } 
    } 

    /** 
    * Performs an HTTP GET request to the specified url. 
    * 
    * @param url The web address to post the request to 
    * @return The result of the request 
    * @throws Exception 
    */ 
    public static String executeHttpGet(String url) throws Exception { 
     BufferedReader in = null; 
     try { 
      HttpClient client = getHttpClient(); 
      HttpGet request = new HttpGet(); 
      request.setURI(new URI(url)); 
      HttpResponse response = client.execute(request); 
      in = new BufferedReader(new InputStreamReader(response.getEntity().getContent())); 

      StringBuffer sb = new StringBuffer(""); 
      String line = ""; 
      String NL = System.getProperty("line.separator"); 
      while ((line = in.readLine()) != null) { 
       sb.append(line + NL); 
      } 
      in.close(); 

      String result = sb.toString(); 
      return result; 
     } finally { 
      if (in != null) { 
       try { 
        in.close(); 
       } catch (IOException e) { 
        e.printStackTrace(); 
       } 
      } 
     } 
    } 
} 

Answer 1

雖然它已被棄用，您仍然可以添加以下內容到搖籃文件中使用它：

android { 
    compileSdkVersion 23 
    buildToolsVersion "23.0.2" 
    useLibrary 'org.apache.http.legacy' 

    ... 
}