在Oracle中id相同時連接記錄

Question

我有Oracle 11 G數據庫。

我的表CHATUSERS看起來是這樣的：

UserId - Identifier 
SeqNum - Order of chat conversation 
ChatText - Chat Text 
DateAdded - DateTime Chat conversation happened. 

的用戶可以在一天內多個聊天會話。 我想結合每人每天的所有ChatText。

例子：

UserId SeqNum DateAdded ChatText 
-------------------------------- 
1  1  28-OCT-14 Hey, How are You? 
1  2  28-OCT-14 Do you have a minute? 
1  3  28-OCT-14 Wanted to talk to you about something. 
1  1  25-OCT-14 Congratulations! 
1  2  25-OCT-14 on your promotion 

所以SELECT查詢將返回的結果爲：我如何做到這一點

UserId, DateAdded and CompleteText 
1 28-OCT-14 Hey, How are You? Do you have a minute? Wanted to talk to you about something. 
1 25-OCT-14 Congratulations! on your promotion 

？

Answer 1

select userid, dateadded, listagg(chattext, ' ') within group (order by seqnum) 
from chatusers 
group by userid, dateadded; 

Answer 2

如果您對11gR2，您可以使用LISTAGG。

 
SELECT UserId, 
       DateAdded, 
       LISTAGG(ChatText, ',') WITHIN GROUP (ORDER BY ChatText) AS CompleteText 
FROM ChatUsers 
GROUP BY UserId, DateAdded; 

其他辦法，看看http://oracle-base.com/articles/misc/string-aggregation-techniques.php