如何解決Winforms Control.Invoke錯誤？

如何解決「Control.Invoke必須用於與一個獨立的線程創建控件交互」錯誤異常如何解決Winforms Control.Invoke錯誤？

Socket serverSocket = new Socket(AddressFamily.InterNetwork, SocketType.Stream, ProtocolType.Tcp); 
serverSocket.Bind(new IPEndPoint(IPAddress.Loopback, portNo)); 
serverSocket.Listen(5); 
Socket client = serverSocket.Accept(); 
MessageBox.Show("Client Connected"); 

//Sent to Client 
NetworkStream ns = new NetworkStream(client); 
StreamWriter writer = new StreamWriter(ns); 
writer.AutoFlush = true; 
writer.WriteLine(sb.ToString()); 

//Receive from Client NetworkStream 
Stream nets = new NetworkStream(client); 
StreamReader reader = new StreamReader(nets); 
string clientIPAddress = reader.ReadLine();

來源

2010-06-13 omn ohnmar

編輯代碼片段以顯示失敗的代碼。 – 2010-06-13 09:39:07

你肯定確定它是導致異常的這一點代碼嗎？實際上（隱式地）創建UI控件的唯一地方是通過調用MessageBox.Show，但我迄今認爲這種方法不必在UI（「main」）線程上運行。你真的在程序中使用多線程嗎？ – stakx 2010-06-13 10:13:32

這樣做出來嗎？這聽起來像你在某種回調，但（由於線程親和力），你可以只有談話控制其相關的線程。所以：

string newAnswer = LongComplexCode(); // on worker thread here 
someControl.Invoke((MethodInvoker) delegate { 
    /* your work here, e.g. */ 
    someControl.Text = newAnswer; // on UI thread here 
});

來源

2010-06-13 08:33:30

// My Coding is， Socket serverSocket = new Socket（AddressFamily.InterNetwork，SocketType.Stream，ProtocolType.Tcp）; serverSocket.Bind（新的IPEndPoint（IPAddress.Loopback，portNo））; serverSocket.Listen（5）; 套接字客戶端= serverSocket.Accept（）; MessageBox.Show（「客戶端連接」）; //發送給客戶端 NetworkStream ns = new NetworkStream（client）; StreamWriter writer = new StreamWriter（ns）; writer.AutoFlush = true; write.WriteLine（sb.ToString（））; //從客戶端接收 NetworkStream nets = new NetworkStream（client）; StreamReader reader = new StreamReader（nets）; string clientIPAddress = reader.ReadLine（）; – 2010-06-13 08:57:57

如何解決Winforms Control.Invoke錯誤？

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