如何將單個字母鏈接到單詞？

Question

我正在創建一個文字遊戲，您必須通過從側面拖動字母來拼出網格中的單詞。

該代碼從「listOfWords」中隨機生成12個字，並動態創建一個6x6表。這句話也分成單個字符（「P」「I」「T」），這樣可拖動字母可以放在拼的話......

var listOfWords = ["mat", "cat", "dog", "pit", "pot", "fog", "log", "pan", "can", "man", "pin", "gag", "sat", "pat", "tap", "sap", "tag", "gig", "gap", "nag", "sag", "gas", "pig", "dig", "got", "not", "top", "pop", "god", "mog", "cot", "cop", "cap", "cod", "kid", "kit", "get", "pet", "ten", "net", "pen", "peg", "met", "men", "mum", "run", "mug", "cup", "sun", "mud", "rim", "ram", "rat", "rip", "rag", "rug", "rot", "dad", "sad", "dim", "dip", "did", "mam", "map", "nip", "tin", "tan", "nap", "sit", "tip", "pip", "sip", "had", "him", "his", "hot", "hut", "hop", "hum", "hit", "hat", "has", "hug", "but", "big", "bet", "bad", "bad", "bed", "bud", "beg", "bug", "bun", "bus", "bat", "bit", "fit", "fin", "fun", "fig", "fan", "fat", "lap", "lot", "let", "leg", "lit"]; 

var shuffledWords = listOfWords.slice(0).sort(function() { 
return 0.5 - Math.random(); 
}).slice(0, 12); 

var tbl = document.createElement('table'); 
tbl.className='tablestyle'; 
var wordsPerRow = 2; 


for (var i = 0; i < shuffledWords.length; i += wordsPerRow) { 
var row = document.createElement('tr'); 

for (var j=i; j < i + wordsPerRow; ++ j) { 
    var word = shuffledWords[j]; 

    for (var k = 0; k < word.length; k++){ 
     var cell = document.createElement('td'); 


     cell.textContent = word[k]; 
     // IF FIREFOX USE cell.textContent = word[j]; INSTEAD 
     row.appendChild(cell); 
    } 
} 
tbl.appendChild(row);  
} 

document.body.appendChild(tbl); 

下面是拖動字母均碼放到網格上拼寫單詞。

<div class="squares"> 

     <div id="drag1" class="drag ui-widget-content box-style2" tabindex="0"> 
     <p>a</p> 
     </div> 

     <div id="drag2" class="drag ui-widget-content box-style" tabindex="0"> 
     <p>b</p> 
     </div> 

     <div id="drag3" class="drag ui-widget-content box-style" tabindex="0"> 
     <p>c</p> 
     </div> 

     <div id="drag4" class="drag ui-widget-content box-style" tabindex="0"> 
     <p>d</p> 
     </div> 

     <div id="drag5" class="drag ui-widget-content box-style2" tabindex="0"> 
     <p>e</p> 
     </div> 

     <div id="drag6" class="drag ui-widget-content box-style" tabindex="0"> 
     <p>f</p> 
     </div> 

     <div id="drag7" class="drag ui-widget-content box-style" tabindex="0"> 
     <p>g</p> 
     </div> 

     <div id="drag8" class="drag ui-widget-content box-style" tabindex="0"> 
     <p>h</p> 
     </div> 

     <div id="drag9" class="drag ui-widget-content box-style2" tabindex="0"> 
     <p>i</p> 
     </div> 

     <div id="drag10" class="drag ui-widget-content box-style" tabindex="0"> 
     <p>j</p> 
     </div> 

     <div id="drag11" class="drag ui-widget-content box-style" tabindex="0"> 
     <p>k</p> 
     </div> 

     <div id="drag12" class="drag ui-widget-content box-style" tabindex="0"> 
     <p>l</p> 
     </div> 

     <div id="drag13" class="drag ui-widget-content box-style" tabindex="0"> 
     <p>m</p> 
     </div> 

     <div id="drag14" class="drag ui-widget-content box-style" tabindex="0"> 
     <p>n</p> 
     </div> 

     <div id="drag15" class="drag ui-widget-content box-style2" tabindex="0"> 
     <p>o</p> 
     </div> 

     <div id="drag16" class="drag ui-widget-content box-style" tabindex="0"> 
     <p>p</p> 
     </div> 

     <div id="drag17" class="drag ui-widget-content box-style" tabindex="0"> 
     <p>r</p> 
     </div> 

     <div id="drag18" class="drag ui-widget-content box-style" tabindex="0"> 
     <p>s</p> 
     </div> 

     <div id="drag19" class="drag ui-widget-content box-style" tabindex="0"> 
     <p>t</p> 
     </div> 

     <div id="drag20" class="drag ui-widget-content box-style2" tabindex="0"> 
     <p>u</p> 
     </div> 

如何讓單詞在頂部放置時識別正確的字母？

東西沿着這些路線....

if ("mat" == drag13 + drag1 + drag19) { 
      return true; 
     } 
     else { 
      return false; 
     } 

Answer 1

我做你拖放啓用的簡化版本。 請注意，在這個例子中，將單詞拆分爲字母是沒有用的（也是不可取的）。

我已經使用了HTML5自定義數據屬性，但是您也可以使用該ID來存儲單詞和字母。

例子：jsFiddle（拖3個字母的單詞）

你也應該在可放開和可拖動閱讀docs。