Python requests是一個很好的模塊,以減輕我的網絡REST API訪問編程,我通常不喜歡下面如何構建來自python請求模塊的curl命令?
import json
url = 'https://api.github.com/some/endpoint'
payload = {'some': 'data'}
headers = {'Content-type': 'application/json', 'Accept': 'application/json'}
r = requests.post(url, data=json.dumps(payload), headers=headers)
當有錯誤出現,我想看看它後面發生什麼。構建curl
命令在命令行再現是常見的方式,因爲這是
try:
r = requests.post(url, data=json.dumps(payload), headers=headers)
except Exception as ex:
print "try to use curl command below to reproduce"
print curl_request(url,"POST",headers,payload)
這將是很好我可以生成此請求curl
命令樣品,其最在RESP API文獻中描述的標準方法,參見在libcloud's debug中很好的例子,我找不到一個簡單的方法來構建,下面是我想自己創建的方法。
# below code is just pseudo code, not correct
def curl_request(url,method,headers,payloads):
# construct curl sample from requests' structure
# $ curl -v -H "Accept: application/json" -H "Content-type: application/json"
# -d '{"some":"data"}'
# -X POST https://api.github.com/some/endpoint
request = "curl -v "
for header in headers:
print header
request = request + '-H "' + header + ": " + headers[header] + '" '
for payload in payloads:
request = request + '-d {} "' + payload + ": " + payloads[payload] + '" '
request = request + "-X %s %s" % (method,url)
return request
這也將是很好,如果我們在requests
有方法已經
下面是最終的解決方案得到了答案,我的作品。在此處顯示以供參考
def curl_request(url,method,headers,payloads):
# construct the curl command from request
command = "curl -v -H {headers} {data} -X {method} {uri}"
data = ""
if payloads:
payload_list = ['"{0}":"{1}"'.format(k,v) for k,v in payloads.items()]
data = " -d '{" + ", ".join(payload_list) + "}'"
header_list = ['"{0}: {1}"'.format(k, v) for k, v in headers.items()]
header = " -H ".join(header_list)
print command.format(method=method, headers=header, data=data, uri=url)
謝謝,這是我想要在示例代碼中做的事情,但它變得很複雜,因爲我需要處理不同類型的數據,上面的頭[頭]可能是整數,你可以粘貼你的示例代碼我參考? –
如果你將整數傳遞給請求而沒有得到異常,我不知道你在做什麼。我可以在我的答案中加入一些示例代碼,它可以在需要工作的python版本上工作(即2.6+) –
謝謝,您的示例代碼對我來說已經足夠好了,並且我使用代碼I在現實中使用。 –