操縱PHP數組

Question

嗨，大家好我有一個填充日期

Array 
(
    [0] => 2012-04-04 
    [1] => 2012-04-06 
    [2] => 2012-04-06 
    [3] => 2012-04-06 
    [4] => 2012-04-06 
    [5] => 2012-04-06 
    [6] => 2012-04-06 
    [7] => 2012-04-11 
    [8] => 2012-04-12 
    [9] => 2012-04-12 
    [10] => 2012-04-13 
    [11] => 2012-04-13 
    [12] => 2012-04-13 
    [13] => 2012-04-13 
    [14] => 2012-04-13 
    [15] => 2012-04-13 
    [16] => 2012-04-13 
) 

數組如何將我遍歷數組，發現在項目之間天差旁邊陣列對方。例如，我想呼應OUT [0]和[1]是 「2」 天之間

差 [1]和[2]爲 「0」 天

之間差

:)

管理從頂部的答案得到一些輸出，但我只希望它顯示，如果有日期的差異。

從這個if語句沒有輸出，但 - 更新 -

$count = count($datestack); 



for ($i = 0; $i < $count - 1; $i++) { 
    $datetime1 = new DateTime($datestack[$i]); 
    $datetime2 = new DateTime($datestack[$i + 1]); 
    $interval = $datetime1->diff($datetime2); 
    if ($arr[$i] === $arr[$i+1]){ 
    echo $interval->format('%R%a days'); 
    } 

} 

Answer 1

你需要的是DateTime::diff。

例子：

$datetime1 = new DateTime('2012-04-04'); 
$datetime2 = new DateTime('2012-04-06'); 
$interval = $datetime1->diff($datetime2); 
echo $interval->format('%R%a days'); 

，你只需要循環的數組做你想做什麼。

$count = count($arr); 
for ($i = 0; $i < $count - 1; $i++) { 
    $datetime1 = new DateTime($arr[$i]); 
    $datetime2 = new DateTime($arr[$i + 1]); 
    $interval = $datetime1->diff($datetime2); 
    echo $interval->format('%R%a days'); 
} 

Answer 2

是這樣的？

 foreach($input as $k=>$i){ if(empty($input[$k-1])) continue; echo "<br /> difference between [".($k-1)."] and [".$k."] is ".'"'.round(abs(strtotime($i)-strtotime($input[$k-1]))/(3600*24)).'"'." days "; }; 

Answer 3

<?php 
    $dates = array(
     '2012-04-04', 
     '2012-04-06', 
     '2012-04-06', 
     '2012-04-06', 
     '2012-04-06', 
     '2012-04-06', 
     '2012-04-06', 
     '2012-04-11', 
     '2012-04-12', 
     '2012-04-12', 
     '2012-04-13', 
     '2012-04-13', 
     '2012-04-13', 
     '2012-04-13', 
     '2012-04-13', 
     '2012-04-13', 
     '2012-04-13' 
    ); 

    array_walk($dates, function($item, $key) { 
     static $previous = null; 
     if ($previous != null) { 
      $datetime1 = new DateTime($previous); 
      $datetime2 = new DateTime($item); 
      $interval = $datetime1->diff($datetime2); 
      echo $interval->format('%R%a days') . "\n"; 
     } 
     $previous = $item; 
    }); 

?>