從文件中讀取序列化對象？

-1

我想從一個對象文件中編寫和讀取一個可序列化的類。我可以將這個對象寫入一個文件，但我似乎無法將對象讀回並寫入控制檯。從文件中讀取序列化對象？

這兩個選項都不起作用。我只想讀取對象，因爲它被寫入對象文件。

代碼嘗試：

public void readBinary1() throws IOException, ClassNotFoundException { 
     ObjectInputStream input = new ObjectInputStream(new FileInputStream 
             ("G:\\testobject.tmp")); 
     input.readObject(); 

     System.out.println(new myClass()); 
    } 

    public void readBinary1() throws IOException, ClassNotFoundException { 
     ObjectInputStream input = new ObjectInputStream(new FileInputStream 
             ("G:\\testobject.tmp")); 

     System.out.println(new myClass(input.readObject())); 
    }

類：

class myClass implements Serializable { 
    myClass() {} 

    myClass(myClass b) { 
     this.a = b.a; 
     this.b = b.b; 
    } 

    private static final long serialVersionUID = 1L; 
    private int a = 0; 
    private int b = 100; 
    private transient int c = 50; 
}

程式碼：

I had to add a toString to my class to do it the way that it was suggested to do. That seems to be the way that is easiest in the short run but I would rather write the object and then be able to read in the object with out having to use the toString. Is there a way that I can read in the object with one read and then be able to break the info apart with the .dot notation. Such as mc.variable1 and mc.variable2 and so on. I had to type cast the read object also before the code would compile.

有幾個輸入和輸出流的，允許用於對象的序列化到文件。我確信有不同的方式來包裝類的閱讀，並想知道哪種方式是創建閱讀的最佳方式。

來源

2014-02-17 Doug Hauf

嘗試搜索在堆棧溢出這樣的問題 - 你確實有很多類似的問題和答案。 –

看到http://stackoverflow.com/questions/17293991/how-to-write-and-read-java-serialized-objects-into-a-file – michael

你似乎不明白你正在閱讀*序列化對象*來自流。 'MyClass mc =（MyClass）input.readObject（）;'。完成。 –

這樣做：

myClass readedObject = (myClass) input.readObject(); 
System.out.println(readedObject);

來源

2014-02-17 22:40:42

從文件中讀取序列化對象？

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