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我在FastCGI的運行Django的模式Django的複製管理前綴的網址
./manage.py runfcgi method=threaded host=127.0.0.1 port=8080
與Nginx的
server {
listen 80;
server_name myhostname.com;
access_log /var/log/nginx/sample_project.access.log;
error_log /var/log/nginx/sample_project.error.log;
location /static/ { # STATIC_URL
alias /home/www/myhostname.com/static/; # STATIC_ROOT
expires 30d;
}
location /media/ { # MEDIA_URL
alias /home/www/myhostname/static/; # MEDIA_ROOT
expires 30d;
}
location/{
include fastcgi_params;
fastcgi_pass 127.0.0.1:8080;
}
}
管理URL是
http://myhostname.com/admin/
我發現,每一個HTML鏈接生成的錯誤如下圖所示
...
<a href="/admin/admin/logout/">Log out</a>
...
下面我url.py
from django.conf.urls import patterns, include, url
from django.contrib import admin
admin.autodiscover()
urlpatterns = patterns('',
# Examples:
# url(r'^$', 'configuratore.views.home', name='home'),
# url(r'^blog/', include('blog.urls')),
url(r'^admin/', include(admin.site.urls)),
)
看來,Django是複製管理URL,但我不明白爲什麼。
你在'settings.py'中做了些奇怪的事嗎? (說定義你自己的'LOGIN_URL'或類似的東西?) – yuvi
不,我沒有。錯誤出現在Nginx配置文件中。請參閱下面的接受答案。 – alesdario