$ _POST中的Php動態變量不會打到

Question

我準備好撕掉我的頭髮了。

基本上我必須創建一個頁面，它讀取文件的目錄並創建一個表單，允許您按下每個文件名旁邊的導入按鈕將文件導入數據庫。

我通過目錄這樣的掃描：

$files=scandir('uploads');//get array of files/directories in uploads 
foreach($files as $file) {//loop through the array 
    if(!is_dir($file)) {//if not a directory must be a file 
     echo $file.'<input type="submit" value="Import CSV File" name="'.$file.'" >'; 
    } 
} 

，比相同的形式（全在一個表格）我做的：

$files=scandir('uploads');//get array of files/directories in uploads 
foreach($files as $file) {//loop through the array 
    if(!is_dir($file)) {//if not a directory must be a file 
     if(isset($_POST[$file])) {//this if never hits 
      echo 'aa'; 
      exit(); 
     } 
    } 
} 

，你可以通過我的意見時，看到我點擊一個按鈕，導入文件的if(isset($_POST[$file]))嗟......

我不知道爲什麼..

這裏是爲了更好地全面瞭解頁面上的一些代碼

import_csv.php：

<?php 
    if(session_id()=='') { 
     session_start(); 
    } 
    // check if user is not logged in thus is most likely not allowed to view the page or login went wrong 
    if(!isset($_SESSION['loggedin'])||$_SESSION['loggedin']===false) { 
     echo '<p>You are not logged in. Please <a href="index.php">login</a> and try again.</p>'; 
     exit();//stops the execution of the php file so we dont show the links below to unauthorized visitors 
    } 

    $files=scandir('uploads');//get array of files/directories in uploads 
    foreach($files as $file) {//loop through the array 
     if(!is_dir($file)) {//if not a directory must be a file 
      if(isset($_POST[$file])) { 
       echo 'aa'; 
       exit(); 
      } 
     } 
    } 
?> 

<h2 align="center">Import CSV Files:</h2> 

<p align="center"> 
This will allow you to view names of uploaded CSV files and import them into the database. 
Below are a list of available files on the server to be imported: 
</p> 

<form method="post" action="import_csv.php"> 

<?php 

    //Create connection and suppress any errors for now using @ 
    $con=@mysqli_connect('localhost','jd','1111','my_db'); 

    // Check connection 
    if (mysqli_connect_errno($con)) { 
     echo 'Could not connect to database.'; 
     exit(); 
    }else { 
     //query all tables in db 
     $sql = "SHOW TABLES FROM my_db;"; 
     $result = mysqli_query($con,$sql); 


     //loop through results/all tables 
     while ($row = mysqli_fetch_row($result)) { 
      if($row[0]=='users'&&isset($_SESSION['user_type']) && $_SESSION['user_type']!='admin') { 
      }else { 
       echo '<input type="checkbox" name="'.$row[0].'" > '.$row[0].'<br></br>'; 
      } 
     } 
    } 

    $files=scandir('uploads');//get array of files/directories in uploads 
    foreach($files as $file) {//loop through the array 
     if(!is_dir($file)) {//if not a directory must be a file 
      echo $file.'<input type="submit" value="Import CSV File" name="'.$file.'" >'; 
     } 
    } 
?> 
</form> 

Answer 1

這是因爲文件擴展名的問題，文件擴展名總是應該的，但是PHP它轉換「」至 '_'。然後請重寫代碼一樣，

$files=scandir('uploads');//get array of files/directories in uploads 
foreach($files as $file) {//loop through the array 
    $postName = str_replace('.','_',$file); 
     if(isset($_POST[$postName])) {//if not a directory must be a file 
      echo 'aa'; 
      exit(); 
     } 
    } 

這裏的$文件應該喜歡FILE.CSV，但PHP請求數組包含$ _ POST [file_csv]