錯誤：溢出在隱恆定轉化率[-Werror =溢出]

Question

錯誤：溢出在隱恆定轉化率[-Werror =溢出]

#include<stdio.h> 

int main() 
{ 
    char ch=200; 
    printf("\n%d",ch); 
    return 0; 
} 

IAM的運行上http://ideone.com/YNkKT6#view_edit_box此代碼和獲取的隱式轉換的錯誤。 我需要做什麼修改，原因是什麼？

Answer 1

n3376 3.9.1/1

Plain char, signed char, and unsigned char are three distinct types. A char, a signed char, and an unsigned char occupy the same amount of storage and have the same alignment requirements (3.11); that is, they have the same object representation.

什麼是char是實現定義的，因此，你需要unsigned char這裏，它處理的值（0-255）。

Answer 2

看起來像你的char是signed char，它接受從-128到127的值。而200對於它來說太大了，並且會溢出成負數。

修復它，改變char到int或unsigned char

int main() 
{ 
    unsigned char ch=200; 
    printf("\n%d",ch); 
    return 0; 
}