Django的模型和MPTT整合

Question

我有一個Django模型，如下所示：在Django的模型deg_course_cat表

from django.db import models 
from mptt.models import MPTTModel, TreeForeignKey 

class deg_course_cat(models.Model): 
    degree_code = models.CharField(max_length=24) 
    specialization = models.CharField(max_length=48) 
    category_level1 = models.CharField(max_length=48) 
    category_level2 = models.CharField(max_length=96) 
    category_level3 = models.CharField(max_length=48) 
    min_credit = models.IntegerField() 
    max_credit = models.IntegerField() 
    primarystuff = models.CharField(max_length=24) 

class deg_course_cat_mptt(MPTTModel): 
    name = models.CharField(max_length=100, unique=False) 
    min_credit = models.IntegerField(null=True) 
    max_credit = models.IntegerField(null=True) 
    parent = TreeForeignKey('self', null=True, blank=True, related_name='children') 

    class MPTTMeta: 
     order_insertion_by = ['name'] 

# Create your models here. 

的數據如下所示：

我想根據模型及其數據創建mptt結構，即類似於以下結構：

我該如何解決這個問題？由於我對python很陌生，如果我能夠實現這一目標，那將會很棒。

我試圖像下面的一些代碼，但我不知道它是如何正確的是：

from studentapp.models import deg_course_cat, deg_course_cat_mptt 

#degreeroot = deg_course_cat_mptt.objects.create(name="DegreeRoot") 

for degrees in deg_course_cat.objects.values_list('degree_code', flat=True): 
    degreearray = set(deg_course_cat.objects.values_list('degree_code', flat=True)) 
    for i in range(0,len(degreearray)): 
     degree(i) = deg_course_cat_mptt.objects.create(name= degreearray(i), parent=degreeroot) 

     for categories_l1 in deg_course_cat.objects.values_list('category_level1', flat=True): 
     category_level1 = set(deg_course_cat.objects.values_list('category_level1', flat=True)) 

      for categories_l2 in deg_course_cat.objects.values_list('category_level2', flat=True): 
      category_level2 = set(deg_course_cat.objects.values_list('category_level2', flat=True)) 

      for categories_l3 in deg_course_cat.objects.values_list('category_level3', flat=True): 
      category_level3 = set(deg_course_cat.objects.values_list('category_level3', flat=True)) 

Answer 1

你可以做這樣的事情this

category_l1_array = list(set(deg_course_cat.objects.filter(degree_code=degree[i]).values_list('category_level1', flat=True)))