bash一次選擇多個答案

Question

我有一個平面文件稱爲項目，我想填充選擇，但我希望能夠一次選擇多個項目。項目

文件內容：

cat 1 
dog 1 
pig 1 
cherry 2 
apple 2 

Basic腳本：

#!/bin/bash 
PS3=$'\n\nSelect the animals you like: ' 
options=$(grep '1' items|grep -v '^#' |awk '{ print $1 }') 

select choice in $options 
do 
    echo "you selected: $choice" 
done 

exit 0 

現在流動是我唯一可以在一次選擇一個選項的方式。我希望能夠回答1,3或1 3，並將它「您選擇：貓豬」迴應

謝謝

Tazmarine

Answer 1

這是我想出了。這似乎符合我的要求。我想用逗號分隔的最終輸出：

#!/bin/bash 

newarray=(all $(grep '1' items|grep -v '^#' |awk '{ print $1 }')) 

options() { 
num=0 
for i in ${newarray[@]}; do 
    echo "$num) $i" 
    ((num++)) 
done 
} 

getanimal() { 
while [[ "$show_clean" =~ [A-Za-z] || -z "$show_clean" ]]; do 
    echo "What animal do you like: " 
    options 
    read -p 'Enter number: ' show 
    echo 
    show_clean=$(echo $show|sed 's/[,.:;]/ /g') 
    selected=$(\ 
    for s in $show_clean; do 
    echo -n "\${newarray[${s}]}," 
    done) 
    selected_clean=$(echo $selected|sed 's/,$//') 
done 
eval echo "You selected $selected_clean" 
} 

getanimal 

exit 0 

Answer 2

你不能這樣做，因爲這樣，但你可以隨時記錄每個個體的選擇：

#!/bin/bash 
PS3=$'\n\nSelect the animals you like: ' 
options=$(grep '1' items|grep -v '^#' |awk '{ print $1 }') 

# Array for storing the user's choices 
choices=() 

select choice in $options Finished 
do 
    # Stop choosing on this option 
    [[ $choice = Finished ]] && break 
    # Append the choice to the array 
    choices+=("$choice") 
    echo "$choice, got it. Any others?" 
done 

# Write out each choice 
printf "You selected the following: " 
for choice in "${choices[@]}" 
do 
    printf "%s " "$choice" 
done 
printf '\n' 

exit 0 

下面是一個例子互動：

$ ./myscript 
1) cat 
2) dog 
3) pig 
4) Finished 

Select the animals you like: 3 
pig, got it. Any others? 

Select the animals you like: 1 
cat, got it. Any others? 

Select the animals you like: 4 
You selected the following: pig cat 

如果改爲希望能夠在同一行上寫3 1，你必須使自己的菜單循環與echo和read