當我有mysql提取assoc時，PHP在表單中提交更多變量？

Question

echo "<form method='post' action='proceed.php'>"; 
while ($row = $stmt->fetch(PDO::FETCH_ASSOC)){ 
    extract($row); 

    echo "<tr>"; 
    echo "<td>{$name}<input type='hidden' name='itemid' value='{$itemid}'></td>"; 
    echo "<td>&#36;{$price}</td>"; 
    echo "<td>"; 
    echo "<a href='remove_from_cart.php?id={$id}&name={$name}' class='btn btn-danger'>"; 
    echo "<span class='glyphicon glyphicon-remove'></span> Remove from cart"; 
    echo "</a>"; 
    echo "</td>"; 
    echo "</tr>"; 
    $total_price+=$price; 
} 
echo"<input type='hidden' name='itemsprice' value='{$total_price}' id='itemsprice'>"; 
echo "<tr>"; 
echo "<td><b>Total</b></td>"; 
echo "<td>&#36;{$total_price}</td>"; 
echo "<td>"; 
echo "<input type='submit'>"; 
echo "</a>"; 
echo "</td>"; 
echo "</tr>"; 
echo "</table>"; 
echo "</form>"; 
} 

你好，基本上我想做的是製作一個PHP cart/shop系統，並且我想讓每一行都發送一個變量給proceed.php，我必須把裏面的mysql取得聯合這個工作？

Answer 1

您需要爲輸入使用數組風格的名字：

echo "<td>{$name}<input type='hidden' name='itemid[]' value='{$itemid}'></td>"; 

然後在proceed.php，$_POST['itemid']將包含所有輸入的數組。