PHP - 按鍵（日期）選擇值，然後返回值總和

Question

我可能有一個愚蠢的問題，但我不知道如何解決我的問題。

我想達到的目標。

我需要按日期（鍵）（具體來說，我對年度感興趣）劃分字段，並計算出每年的總金額（價值）。

我的數組：

Array 
(
    [2017-04-20 15:26:08] => 0.00 
    [2016-10-11 13:52:05] => 0.00 
    [2016-05-26 13:04:14] => 200000.00 
    [2016-05-24 14:32:34] => 0.00 
    [2016-05-24 11:32:17] => 0.00 
    [2016-03-29 19:02:24] => 79800.00 
    [2016-02-16 07:54:38] => 0.00 
    [2015-12-16 19:01:55] => 149900.00 
    [2015-01-30 15:07:38] => 402103.00 
    [2014-11-03 15:13:29] => 0.00 
    [2014-10-15 15:58:44] => 129000.00 
    [2014-10-06 12:44:52] => 0.00 
    [2014-07-28 10:47:45] => 0.00 
    [2014-07-23 15:50:24] => 133333.33 
    [2014-05-16 12:39:25] => 0.00 
    [2014-04-29 13:21:01] => 5045524.00 
    [2014-03-04 15:28:03] => 0.00 
    [2014-01-13 09:41:47] => 0.00 
    [2013-11-26 08:40:20] => 70000.00 
    [2013-07-22 12:17:24] => 0.00 
    [2012-10-05 13:51:06] => 0.00 
    [2012-03-08 15:45:44] => 149880.00 
    [2012-03-02 13:11:19] => 0.00 
    [2012-02-14 09:26:43] => 0.00 
    [2011-12-05 10:44:23] => 0.00 
    [2011-12-05 10:33:53] => 1500000.00 
    [2011-07-01 14:40:22] => 0.00 
    [2011-05-30 09:54:22] => 1680000.00 
    [2011-01-13 08:59:14] => 72000.00 
) 

我的代碼：

$min_year = date('Y',strtotime(min(array_column($MY_ARRAY,'published_at')))); 
$max_year = date('Y',strtotime(max(array_column($MY_ARRAY,'published_at')))); 

for($year = $max_year; $year >= $min_year; $year--){ 
$amount_array = array_column($MY_ARRAY,'contract_amount','published_at'); 

echo 'Year: ' .$year . ', Total amount for this year: ' . ???? . ' €'; 

} 

我應該怎麼辦呢？

編輯//原來陣列的一部分

Array 
(
    [0] => stdClass Object 
     (
      [id] => 2898917 
      [contract_identifier] => 155/AD00/2017 
      [contracting_authority_name] => some company 
      [contracting_authority_formatted_address] => address 
      [contracting_authority_cin] => 123456789 
      [supplier_name] => another company 
      [supplier_formatted_address] => 
      [supplier_cin] => n123456789mber 
      [subject] => contract title 
      [subject_description] => 
      [signed_on] => 2017-04-19 
      [effective_note] => 
      [contract_price_amount] => 0.00 
      [contract_price_total_amount] => 0.00 
      [note] => 
      [published_at] => 2017-04-20 15:26:08 
      [changed_at] => 2017-04-20 15:10:09 
      [change_note] => 
      [internal_id] => 155 
      [internal_note] => 
      [confirmation_file_name] => 
      [confirmed_on] => 
      [source_id] => 2 
      [description] => 
      [reference] => 
      [effective_from] => 2017-04-21 
      [effective_to] => 
      [crz_department_name] => department 
      [crz_status_name] => 1 
      [crz_type_name] => 1 
      [crz_kind_name] => 2 
      [crz_confirmation_status_name] => 5 
      [crz_attachments_title] => 11111 
      [crz_attachments_file_name] => 
      [crz_attachments_file_size] => 
      [crz_attachments_scan_file_name] => 2898918_dokument.pdf 
      [crz_attachments_scan_file_size] => 373463 
     ) 

    [1] => stdClass Object 
     (
      [id] => 2635819 
      [contract_identifier] => 241 
      [contracting_authority_name] => ... 

... ...

Answer 1

我會做一些像這樣：

1. 遍歷整個東西。
2. 創建另一個數組。
3. 獲取日期部分並解析年份。
4. 累計添加年份作爲鍵和值作爲總和。
5. 顯示。

代碼：

<?php 
    $arr = array(
     "2017-04-20 15:26:08" => 0.00, 
     "2016-10-11 13:52:05" => 0.00, 
     "2016-05-26 13:04:14" => 200000.00, 
     "2016-05-24 14:32:34" => 0.00, 
     "2016-05-24 11:32:17" => 0.00, 
     "2016-03-29 19:02:24" => 79800.00, 
     "2016-02-16 07:54:38" => 0.00, 
     "2015-12-16 19:01:55" => 149900.00, 
     "2015-01-30 15:07:38" => 402103.00, 
     "2014-11-03 15:13:29" => 0.00, 
     "2014-10-15 15:58:44" => 129000.00, 
     "2014-10-06 12:44:52" => 0.00, 
     "2014-07-28 10:47:45" => 0.00, 
     "2014-07-23 15:50:24" => 133333.33, 
     "2014-05-16 12:39:25" => 0.00, 
     "2014-04-29 13:21:01" => 5045524.00, 
     "2014-03-04 15:28:03" => 0.00, 
     "2014-01-13 09:41:47" => 0.00, 
     "2013-11-26 08:40:20" => 70000.00, 
     "2013-07-22 12:17:24" => 0.00, 
     "2012-10-05 13:51:06" => 0.00, 
     "2012-03-08 15:45:44" => 149880.00, 
     "2012-03-02 13:11:19" => 0.00, 
     "2012-02-14 09:26:43" => 0.00, 
     "2011-12-05 10:44:23" => 0.00, 
     "2011-12-05 10:33:53" => 1500000.00, 
     "2011-07-01 14:40:22" => 0.00, 
     "2011-05-30 09:54:22" => 1680000.00, 
     "2011-01-13 08:59:14" => 72000.00 
    ); 
    $sum = array(); 
    foreach ($arr as $year => $value) { 
     $year = date('Y', strtotime($year)); 
     if (!isset($sum[$year])) 
      $sum[$year] = 0.0; 
     $sum[$year] += $value; 
    } 
?> 

輸出

array(7) { 
    [2017]=> 
    float(0) 
    [2016]=> 
    float(279800) 
    [2015]=> 
    float(552003) 
    [2014]=> 
    float(5307857.33) 
    [2013]=> 
    float(70000) 
    [2012]=> 
    float(149880) 
    [2011]=> 
    float(3252000) 
} 

Answer 2

會更加的方式更容易做這樣的事情：

$sum = array(); 
foreach ($MY_ARRAY as $date => $value) { 
    $year = substr($date, 0, 4); 
    $sum[$year] = (isset($sum[$year]) ? $sum[$year] : 0) + $value; 
} 
print_r($sum);