我試圖在標籤中打開每個打開的推文,但我的代碼不會超過299條推文。如何在帶tweepy的hashtag中發佈所有推文?
我也試圖從一個特定的時間線,像推文只在2015年5月和2016年7月tweets。有沒有辦法做到這一點在主流程中,或者我應該寫一點代碼呢?
這裏是我的代碼:
# if this is the first time, creates a new array which
# will store max id of the tweets for each keyword
if not os.path.isfile("max_ids.npy"):
max_ids = np.empty(len(keywords))
# every value is initialized as -1 in order to start from the beginning the first time program run
max_ids.fill(-1)
else:
max_ids = np.load("max_ids.npy") # loads the previous max ids
# if there is any new keywords added, extends the max_ids array in order to correspond every keyword
if len(keywords) > len(max_ids):
new_indexes = np.empty(len(keywords) - len(max_ids))
new_indexes.fill(-1)
max_ids = np.append(arr=max_ids, values=new_indexes)
count = 0
for i in range(len(keywords)):
since_date="2015-01-01"
sinceId = None
tweetCount = 0
maxTweets = 5000000000000000000000 # maximum tweets to find per keyword
tweetsPerQry = 100
searchQuery = "#{0}".format(keywords[i])
while tweetCount < maxTweets:
if max_ids[i] < 0:
if (not sinceId):
new_tweets = api.search(q=searchQuery, count=tweetsPerQry)
else:
new_tweets = api.search(q=searchQuery, count=tweetsPerQry,
since_id=sinceId)
else:
if (not sinceId):
new_tweets = api.search(q=searchQuery, count=tweetsPerQry,
max_id=str(max_ids - 1))
else:
new_tweets = api.search(q=searchQuery, count=tweetsPerQry,
max_id=str(max_ids - 1),
since_id=sinceId)
if not new_tweets:
print("Keyword: {0} No more tweets found".format(searchQuery))
break
for tweet in new_tweets:
count += 1
print(count)
file_write.write(
.
.
.
)
item = {
.
.
.
.
.
}
# instead of using mongo's id for _id, using tweet's id
raw_data = tweet._json
raw_data["_id"] = tweet.id
raw_data.pop("id", None)
try:
db["Tweets"].insert_one(item)
except pymongo.errors.DuplicateKeyError as e:
print("Already exists in 'Tweets' collection.")
try:
db["RawTweets"].insert_one(raw_data)
except pymongo.errors.DuplicateKeyError as e:
print("Already exists in 'RawTweets' collection.")
tweetCount += len(new_tweets)
print("Downloaded {0} tweets".format(tweetCount))
max_ids[i] = new_tweets[-1].id
np.save(arr=max_ids, file="max_ids.npy") # saving in order to continue mining from where left next time program run
請簡化代碼以儘可能最小化以說明您的問題。太多的樣板與問題無關。 –
已編輯。感謝您的警告。 –