消息彈出Mvc3與PostSharp的OnException處理問題

Question

1. 我有一些麻煩，返回彈出消息在mvc3 時，一些異常被引發。
2. 我使用PostSharp作爲全局AOP 框架來捕捉異常並處理它們，構建彈出框的文本 。
3. 我已經將ActionResult擴展爲自定義對象，其中的ExecuteResult中的 實現了RenderViewToString方法， 爲messagePopup創建了正確的html代碼。
4. MessagePopup顯示在頁面上，但Action繼續執行。

我該如何阻止它繼續執行本身？

當它失敗我抓住它在全球的

namespace Aop 
{ 
/// <summary> 
/// Handles Aspect Object Programming in all the projects . 
/// The attribute is being injected through Shared AssemblyInfo.cs to all the 
/// relevant Assemblies in the project. 
/// The code of the class is being added to project in compilation time 
/// and by that improves the response time quality 
/// </summary> 
[Serializable] 
[AttributeUsage(AttributeTargets.Assembly | AttributeTargets.Class | 
      AttributeTargets.Method | AttributeTargets.Constructor, 
      AllowMultiple = true, Inherited = false)] 
[MulticastAttributeUsage(MulticastTargets.Method, AllowMultiple = true, 
         AllowExternalAssemblies = true)] 
public sealed class TraceAttribute : OnMethodBoundaryAspect 
{ 
    [Inject] 
    public IReportBLImpl _reportBL { get; set; } 

    public TraceAttribute() { } 

    #region Runtime semantics 

    /// <summary> 
    /// Handles all exception in all the project Ness.DoarKamuti exceptions 
    /// </summary> 
    /// <param name="eventArgs"></param> 
    public override void OnException(MethodExecutionEventArgs eventArgs) 
    { 
    … 
    DefActionResult res = DefActionResult.Create("~/Views/Shared/MessagePopup.ascx",_report , DefConstants.MessageDesign.PopUp, "messagePopupBody"); 

      eventArgs.ReturnValue = res; 
} 

    } 

比它的建設礦井的ActionResult，處理郵件內容

公共類DefActionResult後：ActionResult的 {

public override void ExecuteResult(ControllerContext context) 
    { 
     DefJsonResult model = this.ActionModel; 


     /* If a view name has been specified, render it */ 
     if (!string.IsNullOrEmpty(model.ViewName)) 
      model.ViewHTML = controller.RenderViewToString(model.ViewName, model.ViewModel); 

     JsonResult res = new JsonResult() { Data = model, JsonRequestBehavior = JsonRequestBehavior.AllowGet }; 
     res.ExecuteResult(context); 
    } 
} 

然後我在建立迴應

public static class MVCExtensions 
{ 

    public static string RenderViewToString(this Controller controller, string viewName, object viewData) 
    { 
     //Create memory writer 
     var sb = new StringBuilder(); 
     var memWriter = new StringWriter(sb); 

     //Create fake http context to render the view 
     var fakeResponse = new HttpResponse(memWriter); 

     var fakeContext = new HttpContext(HttpContext.Current.Request, fakeResponse); 
     var fakeControllerContext = new ControllerContext(
      new HttpContextWrapper(fakeContext), 
      controller.ControllerContext.RouteData, 
      controller.ControllerContext.Controller); 

     var oldContext = HttpContext.Current; 
     HttpContext.Current = fakeContext; 

     //Use HtmlHelper to render partial view to fake context 
     var html = new HtmlHelper(new ViewContext(fakeControllerContext, 
      new FakeView(), controller.ViewData, controller.TempData, memWriter), 
      new ViewPage()); 

     html.ViewDataContainer.ViewData = controller.ViewData; 

     html.RenderPartial(viewName, viewData); 

     //Restore context 
     //HttpContext.Current = oldContext; 

     //Flush memory and return output 
     memWriter.Flush(); 
     return sb.ToString(); 
    } 

在返回我的消息彈出窗口之後，它會繼續原來的操作，就好像它沒有粉碎，當然因爲數據源未初始化而崩潰。

我不想用HandleErrorAttribute處理錯誤，因爲它不像PostSharp那樣動態。

如何停止原始請求的遺留物？ （一句話，我正在使用Telerik網格來顯示數據。）

Answer 1

要停止正常進行的方法，請使用args.FlowBehavior.Return。該方法應該已經做到這一點，除非有其他機制使用try/catch，但是你的方面應該將它自己作爲最外層的try/catch。您真的需要使用ILSpy來查看程序集中的最後一個IL（其他反編譯器在此時將不會看到postharp修改），那麼您將能夠看到發生了什麼。如果你有一個動作屬性，那麼我敢打賭它與它有關，因爲postsharp會修改方法，但動作屬性不會，所以它仍然是最外層的流控制器。首先嚐試FlowBehavior。