JavaScript - 每分鐘發送10個承諾？

Question

我該如何在每一分鐘內派遣10個承諾？

我有這方面的動態日期列表中：

var dates = ["2016-08-31T23:00:00.000Z","2016-09-01T23:00:00.000Z","2016-09-02T23:00:00.000Z","2016-09-03T23:00:00.000Z","2016-09-04T23:00:00.000Z","2016-09-05T23:00:00.000Z","2016-09-06T23:00:00.000Z","2016-09-07T23:00:00.000Z","2016-09-08T23:00:00.000Z","2016-09-09T23:00:00.000Z","2016-09-10T23:00:00.000Z","2016-09-11T23:00:00.000Z","2016-09-12T23:00:00.000Z","2016-09-13T23:00:00.000Z","2016-09-14T23:00:00.000Z","2016-09-15T23:00:00.000Z","2016-09-16T23:00:00.000Z","2016-09-17T23:00:00.000Z","2016-09-18T23:00:00.000Z","2016-09-19T23:00:00.000Z","2016-09-20T23:00:00.000Z","2016-09-21T23:00:00.000Z","2016-09-22T23:00:00.000Z","2016-09-23T23:00:00.000Z","2016-09-24T23:00:00.000Z","2016-09-25T23:00:00.000Z","2016-09-26T23:00:00.000Z","2016-09-27T23:00:00.000Z","2016-09-28T23:00:00.000Z","2016-09-29T23:00:00.000Z","2016-09-30T23:00:00.000Z","2016-10-01T23:00:00.000Z"]; 

我想要得到的內容或結果與這些日期相關聯。但我不想一口氣拿到它們，但是每一分鐘都會有10件物品，直到日期不再。

這是我的工作代碼：

 var promises = dates.map(function (date, i) { 
     return getContent(date); 
    }); 

    Promise.all(promises).then((data) => { 
     console.log(data); 
    }).catch((err) => { 
     console.log(err.message); 
    }); 

它得到連續的內容，不正是我想要的。

但是有可能實現我所需要的嗎？有任何想法嗎？

注：

getContent(date)含有大量的async await諾言，這樣在promse.all調用它必須是一個promise嫌我猜，否則我可以在一個地方的所有返回數據（這是console.log(data); ）當承諾結束時。

編輯：

const delayValue = (val, ms) => { 
    new Promise(resolve => { 
     setTimeout(resolve.bind(null, val), ms) 
    }); 
} 

Answer 1

一個Promise只能解析一次，所以如果你需要每分鐘都有結果，和想用promises做到這一點，你需要對每個數據塊都有一個單獨的承諾。

這裏是你如何能做到這一點通過反覆營造了一個承諾使用自定義delayValue功能：

const delayValue = (val, ms) => 
 
    new Promise(resolve => setTimeout(resolve.bind(null, val), ms)); 
 

 
async function loopDates(dates, chunk, delay) { 
 
    for (let i = 0; i < dates.length; i += chunk) { 
 
     console.log(await delayValue(dates.slice(i, i+chunk), i ? delay : 0)); 
 
    } 
 
} 
 

 
var dates = ["2016-08-31T23:00:00.000Z", "2016-09-01T23:00:00.000Z", "2016-09-02T23:00:00.000Z", "2016-09-03T23:00:00.000Z", "2016-09-04T23:00:00.000Z", "2016-09-05T23:00:00.000Z", "2016-09-06T23:00:00.000Z", "2016-09-07T23:00:00.000Z", "2016-09-08T23:00:00.000Z", "2016-09-09T23:00:00.000Z", "2016-09-10T23:00:00.000Z", "2016-09-11T23:00:00.000Z", "2016-09-12T23:00:00.000Z", "2016-09-13T23:00:00.000Z", "2016-09-14T23:00:00.000Z", "2016-09-15T23:00:00.000Z", "2016-09-16T23:00:00.000Z", "2016-09-17T23:00:00.000Z", "2016-09-18T23:00:00.000Z", "2016-09-19T23:00:00.000Z", "2016-09-20T23:00:00.000Z", "2016-09-21T23:00:00.000Z", "2016-09-22T23:00:00.000Z", "2016-09-23T23:00:00.000Z", "2016-09-24T23:00:00.000Z", "2016-09-25T23:00:00.000Z", "2016-09-26T23:00:00.000Z", "2016-09-27T23:00:00.000Z", "2016-09-28T23:00:00.000Z", "2016-09-29T23:00:00.000Z", "2016-09-30T23:00:00.000Z", "2016-10-01T23:00:00.000Z"]; 
 

 
loopDates(dates, 10, 2000);

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我們的getContent因素加進去，你會做map像你做了（雖然語法可以縮短），然後在每個塊上應用Promise.all：

const delayValue = (val, ms) => 
 
    new Promise(resolve => setTimeout(resolve.bind(null, val), ms)); 
 

 
// Mock for getContent: 
 
const getContent = date => Promise.resolve(date); 
 
    
 
async function loopDates(dates, chunk, delay) { 
 
    const promises = dates.map(getContent); 
 
    
 
    for (let i = 0; i < dates.length; i += chunk) { 
 
     console.log(await delayValue(Promise.all(promises.slice(i, i+chunk)), 
 
            i ? delay : 0)); 
 
    } 
 
} 
 

 
var dates = ["2016-08-31T23:00:00.000Z", "2016-09-01T23:00:00.000Z", "2016-09-02T23:00:00.000Z", "2016-09-03T23:00:00.000Z", "2016-09-04T23:00:00.000Z", "2016-09-05T23:00:00.000Z", "2016-09-06T23:00:00.000Z", "2016-09-07T23:00:00.000Z", "2016-09-08T23:00:00.000Z", "2016-09-09T23:00:00.000Z", "2016-09-10T23:00:00.000Z", "2016-09-11T23:00:00.000Z", "2016-09-12T23:00:00.000Z", "2016-09-13T23:00:00.000Z", "2016-09-14T23:00:00.000Z", "2016-09-15T23:00:00.000Z", "2016-09-16T23:00:00.000Z", "2016-09-17T23:00:00.000Z", "2016-09-18T23:00:00.000Z", "2016-09-19T23:00:00.000Z", "2016-09-20T23:00:00.000Z", "2016-09-21T23:00:00.000Z", "2016-09-22T23:00:00.000Z", "2016-09-23T23:00:00.000Z", "2016-09-24T23:00:00.000Z", "2016-09-25T23:00:00.000Z", "2016-09-26T23:00:00.000Z", "2016-09-27T23:00:00.000Z", "2016-09-28T23:00:00.000Z", "2016-09-29T23:00:00.000Z", "2016-09-30T23:00:00.000Z", "2016-10-01T23:00:00.000Z"]; 
 

 
loopDates(dates, 10, 2000);

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Answer 2

如果您使用的承諾，然後堅持，創建了一套超時解析器的承諾。

裏面彈出數組，並做任何你喜歡的。承諾所有這些承諾都可以做到我想的。

但爲什麼承諾，而不是一個簡單的循環與設置超時？