我們試圖序列化一個對象樹。雖然我們取得了成功。我希望找到一種方法來簡化生成的XML。如何刪除DataContractSerializer詳細信息
的物體看起來像下面這樣:
public class RuleSet<T>
{
public IEnumerable<IState<T>> States { get; set; }
public IEnumerable<ICondition<T>> Conditions { get; set; }
}
public class State<T> : IState<T>
{
public string Id { get; set; }
public List<ITransition<T>> Transitions { get; set; }
}
public class Transition<T> : ITransition<T>
{
public ICondition<T> Condition { get; set; }
public IState<T> Next { get; set; }
}
public class Condition<T> : ICondition<T>
{
public string Id { get; set; }
public string Name { get; set; }
}
我們用一個非常簡單的序列化代碼的時刻:
public void blah()
{
var condition1 = new Condition<object>() {
Id = "C1", AttributeName = "Foo", ExpectedValue = "Bar"
};
var condition2 = new Condition<object>() {
Id = "C2", AttributeName = "Bar", ExpectedValue = "Foo"
};
var state1Transitions = new List<ITransition<object>>();
var state2Transitions = new List<ITransition<object>>();
var state3Transitions = new List<ITransition<object>>();
var state = new State<object> {
Id = "S1", Transitions = state1Transitions
};
var state2 = new State<object> {
Id = "S2", Transitions = state2Transitions
};
var state3 = new State<object> {
Id = "S3", Transitions = state3Transitions
};
state1Transitions.Add(new Transition<object> {
Condition = condition1, Next = state2
});
state1Transitions.Add(new Transition<object> {
Condition = condition2, Next = state3
});
state2Transitions.Add(new Transition<object> {
Condition = condition2, Next = state3
});
var ruleSet = new RuleSet<object> {
States = new List<IState<object>> {state, state2, state3},
Conditions = new List<ICondition<object>>{condition1, condition2}
};
var stream1 = new MemoryStream();
var serializer = new DataContractSerializer(typeof(RuleSet<object>),
new List<Type> {
typeof(State<object>),
typeof(Transition<object>),
typeof(AttributeEqualTo<object>)
});
serializer.WriteObject(stream1, ruleSet);
stream1.Position = 0;
var xml = new StreamReader(stream1).ReadToEnd();
Console.WriteLine(xml);
}
當生成每個級別的輸出的XML完成而不是僅包含對象的引用。基本上每個Transition<T>
我們都會爲每個狀態和條件獲得一個完整的對象定義,即使它們是在別處定義的。
有沒有辦法讓那些只是引用?