PHP類和jQuery

Question

我有簡單的自動完成的JQuery

$(document).ready(function() { 
$(".autocomplete").each(function() { 
    $(this).autocomplete({ 
     source: '/php/LiveSearch2.php?name='+ $(this).attr('name') + '&', 
     minLength: 1, 
     appendTo: "#container" 
    }); 
}); 
}); 

我寫PHP類推值，但它不工作。我在某處犯了一些錯誤。下面是LiveSearch2.php

<?php 

class swapnil { 

private $testname; 
public $json; 

public function __construct { 
    $this->testname = array('swapnil','ranadive'); 
    $this->json = json_encode($this->testname); 
    echo $this->json; 

} 
} 

$Business = new swapnil(); 
?> 

當我使用php代碼沒有類它工作正常。

<?php 
$testname = array('swapnil', 'ranadive'); 
$json = json_encode($testname); 

echo $json 
?> 

Answer 1

__construct之後括號丟失。這裏試試這個：

class swapnil { 

private $testname; 
public $json; 

public function __construct() { 
    $this->testname = array('swapnil','ranadive'); 
    $this->json = json_encode($this->testname); 
    echo $this->json; 

} 
} 

$Business = new swapnil();